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weeeeeb [17]
3 years ago
7

Which of the following statements is true of an essay's conclusion?

Mathematics
1 answer:
laiz [17]3 years ago
8 0
The answer is option D.
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julsineya [31]
The tree is 7.5ft because it's shadow is half it's height.
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3 years ago
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ALGEBRA<br> EQUATION<br> PLEASE HELP ASAP<br><br> -3=12y-5(2y-7)
Dovator [93]

Simplify:

−3=12y−5(2y−7)

−3=12y+(−5)(2y)+(−5)(−7)(Distribute)

−3=12y+−10y+35

−3=(12y+−10y)+(35)(Combine Like Terms)

−3=2y+35

Flip the equation.

2y+35=−3

Subtract 35 from both sides.

2y+35−35=−3−35

2y=−38

Divide both sides by 2.

2y/2=−38/2

y=−19


3 0
3 years ago
Read 2 more answers
Please help me guys!!
Temka [501]

Answer:

The bottom left box is 2.997, and then I guess you can do 0+3=3 for the right side

Step-by-step explanation:

With the boxes given, you do math for the left side to get 2.997. and then for the right side, if you are rounding to the nearest whole number, do 0+3=3. without context it is pretty confusing

6 0
3 years ago
Given a triangle with perimeter 63 cm, one side of which is 21 cm, and one of the medians is perpendicular to one of its angle b
Rainbow [258]

Answer:

The lengths of all sides of the triangle will be 21 cm, 21 cm, and 21 cm

Step-by-step explanation:

Given that the perimeter of the triangle = 63 cm

And the length of one side = 21 cm

and one of the medians is perpendicular to one of its angle bisectors

Since triangle has 3 sides,

Median = 63 ÷ 3 = 21

Therefore each side length = 21 cm

7 0
3 years ago
Which equation does this image represent?
nirvana33 [79]

Given:

Image of the ellipse

To find:

The equation of the image

Solution:

The given image is a ellipse.

Center of the ellipse = (0, 0)

x-axis points are (-3, 0) and (3, 0).

y-axis points are (2, 0) and (-2, 0).

Standard form of equation of ellipse:

$\frac{(x-h)^{2}}{a^{2}}+\frac{(y-k)^{2}}{b^{2}}=1

where (h, k) is the center = (0,0)

a is the point on x-axis where y = 0. Hence a = 3.

b is the point on y-axis where x = 0. Hence b = 2.

Substitute this in the standard form of ellipse.

$\frac{(x-0)^{2}}{3^{2}}+\frac{(y-0)^{2}}{2^{2}}=1

$\frac{x^{2}}{9}+\frac{y^{2}}{4}=1

To make the denominator same multiply 1st term by \frac{4}{4} and 2nd term by \frac{9}{9}.

$\frac{4x^{2}}{4\times9}+\frac{9y^{2}}{9\times4}=1

$\frac{4x^{2}}{36}+\frac{9y^{2}}{36}=1

$\frac{4x^{2}+9y^{2}}{36}=1

Multiply by 36 on both sides

$\frac{4x^{2}+9y^{2}}{36}\times 36=1\times 36

${4x^{2}+9y^{2}}={36}

The equation of the image is ${4x^{2}+9y^{2}}={36}.

8 0
4 years ago
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