So for example we have
1/2 divided by 1/6
What we will do it’s
Leave the first one As it is
Turn the second fraction (the one you want to divide by) upside down
The change the divide to multiply
Multiply the first fraction by that reciprocal
Simplify the fraction (if needed)
So it’s will be like this
1/2 x 6/1 = 6/2
Simplify it
6/2 =3
I hope it’s will help u ✨
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
<u>Algebra I</u>
<u>Calculus</u>
Derivatives
Derivative Notation
Derivative of a constant is 0
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Product Rule]: ![\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bf%28x%29g%28x%29%5D%3Df%27%28x%29g%28x%29%20%2B%20g%27%28x%29f%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>

<u>Step 2: Differentiate</u>
- [Derivative] Product Rule:
 + (-8s - 9)\frac{d}{ds}[(-4s + 2)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20h%27%28s%29%20%3D%20%5Cfrac%7Bd%7D%7Bds%7D%5B%28-8s%20-%209%29%5D%28-4s%20%2B%202%29%20%2B%20%28-8s%20-%209%29%5Cfrac%7Bd%7D%7Bds%7D%5B%28-4s%20%2B%202%29%5D)
- [Derivative] Basic Power Rule:

- [Derivative] Simplify:

- [Derivative] Distribute [Distributive Property]:

- [Derivative] Combine like terms:

Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Derivatives
Book: College Calculus 10e
Answer:
12.3 + 0.61 +100= 112.91
Step-by-step explanation:
All you have to do is make all the values have two place values and then add.
680 I think because if you add what happened to him and then minus it you get 170 but the injuries added together is 680 Im not sure if that's all that you need but I hope this helps XD
Answer:
5832 ways
Step-by-step explanation:
Since the circle has 8 sectors and there is 4 colour,
Assuming the sectors are numbered 1 to 8,
Sector 1 : can be coloured with any of the 4 colour in 4 ways
Sector 2 can be coloured with any of the remaining 3 colours in 3 ways
Sector 3 in 3 ways without using the colour in sector 2
Sector 4 in 3 ways without using the colour in sector 3
Sector 5 in 3 ways without using the colour in sector 4
Sector 6 in 3 ways without using the colour in sector 5
Sector 7 in 3 ways without using the colour in sector 6
Sector 8 in 2 ways without using the colours in sector 1 and 7
Number of ways of colouring = 4*3*3*3*3*3*3*2 = 5832 ways