Question

Please help! Can anyone help me out with this question?

Answer 1

Answer:

$\displaystyle h'(s) = 64s + 20$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Distributive Property

Algebra I

• Terms/Coefficients

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

• f(x) = cxⁿ
• f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                                  $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle h(s) = (-8s - 9)(-4s + 2)$

Step 2: Differentiate

1. [Derivative] Product Rule:                                                                               $\displaystyle h'(s) = \frac{d}{ds}[(-8s - 9)](-4s + 2) + (-8s - 9)\frac{d}{ds}[(-4s + 2)]$
2. [Derivative] Basic Power Rule:                                                                       $\displaystyle h'(s) = (1 \cdot -8s^{1 - 1} - 0)(-4s + 2) + (-8s - 9)(1 \cdot -4s^{1 - 1} - 0)$
3. [Derivative] Simplify:                                                                                         $\displaystyle h'(s) = (-8)(-4s + 2) + (-8s - 9)(-4)$
4. [Derivative] Distribute [Distributive Property]:                                              $\displaystyle h'(s) = 32s - 16 + 32s + 36$
5. [Derivative] Combine like terms:                                                                     $\displaystyle h'(s) = 64s + 20$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e