Name the similar triangles.<br><br><br> ΔABC ~ ΔDEF ΔABC ~ ΔEFD ΔABC ~ ΔDFE ΔABC ~ ΔFED

A family plans a road trip from Fairbanks to Newbury. The distance between the two cities is 240 miles when traveling on the hig

alex41 [277]

Using proportions, it is found that the family will drive 482.8 km on the new route.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In this problem, the family travels a distance of 125% of 240 miles, hence the distance is:

D = 1.25 x 240 = 300 miles.

Since there are are approximately <u>48.28 kilometers in 30 miles</u>, and 300/30 = 10, the distance in kilometers is given by:

D = 48.28 x 10 = 482.8 km.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

8 0

2 years ago

3,6,2,9 use each digit once,make the smallest 4digit number

Andrei [34K]

Answer:

2369

Step-by-step explanation:

3 0

3 years ago

A bank is trying to determine which model of safe to install. The bank manager believes that each model is equally resistant to

alexandr402 [8]

Answer:

So on this case the 95% confidence interval would be given by (-1.152;5.152).

$-1.152 < \mu_{safe1}-\mu_{safe2}$

Should we conclude that the average time it takes experts to crack the safes does not differ by model at the 5% significance level?

A) Yes, the 95% confidence interval for ?D contains 0.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution

Let put some notation

x=value for Safe 1 , y = value for Safe 2

x: 103, 90, 64, 120, 104, 92, 145, 106, 76

y: 101, 94, 58, 112, 103, 90, 140, 110, 74

The first step is calculate the difference $d_i=x_i-y_i$ and we obtain this:

d: 2, -4, 6, 8, 1, 2, 5, -4, 2

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{18}{9}=2$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =4.093$

The next step is calculate the degrees of freedom given by:

$df=n-1=9-1=8$

Now we need to calculate the critical value on the t distribution with 8 degrees of freedom. The value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , so we need a quantile that accumulates on each tail of the t distribution 0.025 of the area.