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r-ruslan [8.4K]
3 years ago
8

57 is 6 percent of what number?

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
8 0
6% of 57 = 3.42 
Six percent of Fifty-Seven even is Three point Forty-Two.
I calculated Six Percent of Fifty-Seven even. Not Fifty-Seven point one, just Fifty-Sevn even. (57.00) 
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y_{-2}=5\cdot(-2)-8=-10-8=-18y=5x-812=5x-812+8=5x20=5xx=\frac{20}{5}x=4

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What is -w(2w+7) distributive property
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Find the area of the regular polygon. Round to the nearest tenth.
mojhsa [17]

Given:

Side length = 12 in

To find:

The area of the regular polygon.

Solution:

Number of sides (n) = 6

Let us find the apothem using formula:

$a=\frac{s}{2 \tan \left(\frac{180^\circ}{n}\right)}

where s is side length and n is number of sides.

$a=\frac{12}{2 \tan \left(\frac{180^\circ}{6}\right)}

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The area of the regular polygon is 374.1 in².

4 0
3 years ago
Claire is painting some doors that are all the same size. She used 2 liters of paint to cobe 1 3/5 doors. How many liters of pai
Deffense [45]

Answer:

1 \dfrac{1}{4} \ liters

Step-by-step explanation:

Given that:

Claire uses 2 liters of paint to cover 1 3/5 doors

Then in order for her to paint 1 door, She will need:

2 L = 1 3/5 door

x L = 1 door

x (L) = \dfrac{2 L \times 1 door }{ 1 \dfrac{3}{5}   \ door}

x (L) = \dfrac{2 L  }{ 1 \dfrac{3}{5}  }

x (L) = \dfrac{2 L  }{  \dfrac{8}{5}  }

x (L) = \dfrac{2 L\times 5  }{  8  }

x (L) = \dfrac{10 \ L }{  8  }

x(L) =1 \dfrac{1}{4} \  L

4 0
2 years ago
If two of these shapes are randomly chosen, one after the other without replacement, what is the probability that the first will
aleksandrvk [35]

Answer:

P(T\ n\ S) = \frac{1}{14}

Step-by-step explanation:

*Missing Part of the Question*

4 stars

5 triangles

3 circles

3 squares

Required

Determine the probability of triangle being first then square being second

Total = 4 + 5 + 3 + 3

Total = 15

Represent the triangle with T and square with S

So, we're solving for P(T n S)

P(T\ n\ S) = P(T) * P(S)

Solving for P(T)

P(T) = \frac{n(T)}{Total}

P(T) = \frac{5}{15}

Solving for P(S)

The question implies a probability without replacement;

Hence Total has now been reduced by 1

Total = 14

P(S) = \frac{n(S)}{Total}

P(S) = \frac{3}{14}

Recall that

P(T\ n\ S) = P(T) * P(S)

P(T\ n\ S) = \frac{5}{15} * \frac{3}{14}

P(T\ n\ S) = \frac{15}{15 * 14}

P(T\ n\ S) = \frac{1}{14}

Hence, the required probability is

P(T\ n\ S) = \frac{1}{14}

3 0
3 years ago
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