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Liula [17]
4 years ago
14

The length of a rectangle is I and the width of the rectangle is W.

Mathematics
1 answer:
Elenna [48]4 years ago
6 0

Answer:

mark me brainliest and ill tell you

Step-by-step explanation:

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The force in Newtons acting on a particle located x meters from the origin is given by the function F(x)=12x2+7. What is the wor
Shkiper50 [21]

W = \displaystyle \int^{5}_{2}   F(x) ~ dx\\\\\\= \displaystyle \int^{5}_{2} \left(12x^2 +7\right) ~dx\\\\\\= 12\displaystyle \int^{5}_{2} x^2 ~dx + \displaystyle \int^{5}_{2} 7~ dx\\\\\\=12 \left[\dfrac{x^3}3 \right]^{5}_{2}  + 7\left[x\right]^{5}_{2}\\\\\\=4(5^3-2^3) + 7(5-2) = 468 + 21 = 489~ J

5 0
2 years ago
Eric scored 95% on his math test. He got 19 problems correct. How many questions were on the test?
Leviafan [203]

i'm pretty sure it's 20.

8 0
3 years ago
Write a mathematical sentence that expresses the information given below . Use t as your variable name.Necessary type <= to m
miskamm [114]

Answer:

t + 8° > 82°

Step-by-step explanation:

Given that :

Let t = temperature when Susanne checks at 11:00

If t rises by 8 more degrees, it will break the record high temperature for that day

Record high temperature for the day = 82 degree

Hence,

Temperature at 11:00 + 8° > record high temperature for the day

t + 8° > 82°

6 0
3 years ago
Almonds cost $3.49 per pound a bag of almonds cost $6.95 to the nearest whole pound about how many pounds of almonds are in the
Kryger [21]

Answer:

The hint in this problem is the word "about" or approximately how many pounds. So we could find the solution by estimation through rounding off. We know that almonds cost about 3.50 per pound and a bag costs about $7.00. Dividing 7 by 3.50 per pound, will give us $7 ÷ $3.50 = 2 pounds.

The answer is 2 pounds.

5 0
3 years ago
Please help me I will really appreciate it!!!
slega [8]

Answer:

<em />\displaystyle  r=\sqrt[3]{\frac{3V}{4\pi}}<em />

<em>The last option matches the correct solution</em>

Step-by-step explanation:

<u>Equation Solving</u>

We have the following equation:

\displaystyle V=\frac{4}{3}\pi r^3

And it's required to solve it for r.

Solving this equation needs to perform some operations to have the r isolated from any other variables or constants.

It can be done by conveniently operating on both sides as follows:

Eliminate the denominator by multiplying by 3:

\displaystyle 3V=4\pi r^3

Move 4\pi to the other side by dividing by 4\pi:

\displaystyle \frac{3V}{4\pi}= r^3

Swapping sides to have r at the left side:

\displaystyle  r^3=\frac{3V}{4\pi}

Finally, take the cubic root and leave r alone:

\displaystyle  r=\sqrt[3]{\frac{3V}{4\pi}}

The last option matches the correct solution

5 0
3 years ago
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