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Brilliant_brown [7]
3 years ago
14

Hughes has a debit balance of $5,000 in its Allowance for Doubtful Accounts before any adjustments are made at the end of the ye

ar. Based on the review and aging of its accounts receivable at the end of the year, Hughes estimates that $60,000 of its receivables are uncollectible. In this situation, the amount of bad debt expense that should be reported for the year is?
Mathematics
1 answer:
bixtya [17]3 years ago
7 0

Answer:

Bad  debt expense : $ (55,000)

Step-by-step explanation:

Allowance  : $ 5000

Uncollected receivables : $ (60,000)

Bad  debt expense : $ (55,000)

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The growth of 100 young trees near a river is given below. At most 50 yards from the river (Event Y) More than 50 yards from the
Alona [7]

Answer:

It is 91% more likely that the tree was atmost 500 yards from the river.

<h3>Step-by-step explanation:</h3>

We are given with distance and height of 100 young trees near a river.

From that table, in total there are 55 trees which grow more than 3 ft during the year.

And among those 55 trees, 50 trees are atmost 50 yards from river.

Hence it is ≈91% more likely that the tree was atmost 50 yards from the river.

4 0
3 years ago
Write the equation of the sphere in standard form. x^2 + y^2 + z^2 + 2x − 4y − 6z = 22
madam [21]

The equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Given equation of sphere be x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We are required to express the given equation in the standard form of the equation of sphere.

Equation is basically relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation,quadratic equation, cubic equation or many more depending on the powers of variables. The standard form of the equation of sphere looks like  x^{2} +y^{2} +z^{2} =r^{2}.

The given equation is x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We have to break 22 which is in right side into various parts according to the left side of the equation.

x^{2} +y^{2} +z^{2} +2x-4y-6z=-1-4-9+36

x^{2} +y^{2} +z^{2} +2x-4y-6z+1+4+9=36

x^{2} +1+2x+y^{2}+4-4y+z^{2} +9-6z=36

x^{2} +(1)^{2} +2*1*x+y^{2} +(2)^{2} -2*2y+z^{2} +(3)^{2} -2*3z=36

(x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}

Hence the equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Learn more about equations at brainly.com/question/2972832

#SPJ4

7 0
1 year ago
What is the answer?
Bad White [126]

Answer:

k=3

Step-by-step explanation:

+ we note f(p)= p^{4}+p^{2}  +p -k

+ Because of "p-1 is a factor of f(p)", that means f(p)= (p-1)* g(p)

Then we have f(1)= (1-1)*g(1)= 0* g(1)= 0

+ We replace p=1 in f(p) and we have:

f(1)=0

that means: 1^{4}+1^{2} + 1 - k=0

then 1+1+1-k = 0, 3-k=0 or k=3

Hope that useful for you.

8 0
3 years ago
The equation of line A is y = 7x + 12. Line B is perpendicular to line A and passes through the point . What would be the soluti
max2010maxim [7]
Since B is perpendicular to A. We can say that the gradient of B will be -1/7 (product of the gradients of 2 perpendicular lines has to be -1).
Now we know that the equation for B is y=-(1/7)x + c with c being the y intercept.
Since the point isnt specified in the question, we could leave the equation like this.
But if there is a given point that B passes through, just plug in the x and y values into their respective places and solve to find c. That should give you the equation for b.
Now, to find the solution of x, we have 2 equations:
1) y=7x+12
2)y=-(1/7)x+c

In this simultaneous equation we see that y is equal to both the expressions. So,
7x+12=-(1/7)x+c

Now, since the value of c is not found, we cannot actually find the value of x, but if we would find c, we could also find x since it would only be a matter of rearranging the equation.
And there you go, that is your solution :)
3 0
3 years ago
PLEASE HELP ASAP!!!!!!
statuscvo [17]

Answer:

24 sides

Step-by-step explanation:

a polygon cannot have a decimal number of sides, it is impossible

since the sum of these exterior angles in a regular polygon must equal 360 degrees. The maximum number of sides that would yield exterior angles that are integers is 360

because 360 ÷ 360 = 1.

4 0
2 years ago
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