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Brilliant_brown [7]

3 years ago

14

Hughes has a debit balance of $5,000 in its Allowance for Doubtful Accounts before any adjustments are made at the end of the ye

ar. Based on the review and aging of its accounts receivable at the end of the year, Hughes estimates that $60,000 of its receivables are uncollectible. In this situation, the amount of bad debt expense that should be reported for the year is?

1 answer:

bixtya [17]3 years ago

7 0

Answer:

Bad debt expense : $ (55,000)

Step-by-step explanation:

Allowance : $ 5000

Uncollected receivables : $ (60,000)

Bad debt expense : $ (55,000)

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You have a deck of cards and select two

scoundrel [369]

Answer:

Step-by-step explanation:

7 0

3 years ago

Will give brainiest answer, I need step-by-step answer

Korvikt [17]

Answer: Choice A

The volume expression is 4/3 times pi times (3x)^3

===================================================

The volume of a sphere is found through the formula

V = (4/3)*pi*r^3

so we start with the fraction 4/3, multiply it with pi, and then multiply it with r^3

In this case, the radius is r = 3x because this is half of the diameter d = 6x

We simply replace the r with 3x in that formula above

V = (4/3)*pi*r^3

V = (4/3)*pi*( r )^3

V = (4/3)*pi*(3x)^3 ... replace r with 3x

6 0

3 years ago

How would you describe the shape of the normal distribution?

RUDIKE [14]

The shape of the normal distribution is bell shape and it is also symmetrical from the left and right sides about the origins (mean).

What is a normal distribution?

A normal distribution is a function on some random variables, which represent the set of all those random variables in a symmetrical bell shape about the mean value.

It shows that the probability of occurrence of some data which is distributed over a function is more at or around the mean.

It is also known as probability distribution curve.

The normal distribution has two parameters:

Mean

Standard deviation

What is the shape of the normal distribution?

The normal distribution curve is at it's peak at the mean value. This shows that the probability of occurrence of the data or value is more concentrated or distributed about the mean. It is also symmetric about the mean. As we more further from the mean, we see that the normal distribution curve gradually decreases showing that the probability of occurrence of the data or the values decreases. The shape that this curve forms is like a bell-shaped. So the shape of normal distribution is bell shape.

Hence, the shape of the normal distribution is bell shape and it is also symmetrical from the left and right sides about the origins (mean).

Know more about "normal distribution" here: brainly.com/question/15103234

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5 0

1 year ago

The sum of two consecutive integers is 65. what are the two integers? show steps please.

Gnoma [55]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the two integers, given that they are consecutive, and their sum is 65.

$\triangle~\fbox{\bf{KEY:}}$

Consecutive integers are right next to each other, like 12 and 13. or 65 and 66.

Let the first integer be x, and let the second integer be x+1.

Their sum is 65. Let's set up our equation:

$\longmapsto\sf{x+x+1=65}$

Combine like terms:

$\longmapsto\sf{2x+1=65}$

Subtract 1 from both sides of the equal sign:

$\longmapsto\sf{2x=64}$

Divide both sides by 2:

$\longmapsto\sf{x=32}$

To find the second integer, subtract the first integer from the sum of the two integers:

$\longmapsto\pmb{65-32}$

$\longmapsto\pmb{33}$

The integers are: 33 and 32.

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

7 0

2 years ago

An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample

valentina_108 [34]

Answer:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

Replacing we got:

$\bar X=58.875$ represent the mean

$s=5.083$ represent the sample standard deviation for the sample

$n=8$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha=0.1$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:

Null hypothesis: $\mu \geq 60$

Alternative hypothesis: $\mu < 60$

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0

3 years ago