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Jet001 [13]
3 years ago
13

The base of a triangle is 3 cm longer than its altitude. The area of the triangle is 35cm^2. Find the altitude. (Hint: use the a

rea of a triangle. 1/2 * base * altitude.)
Mathematics
1 answer:
klemol [59]3 years ago
7 0
The base is 3+(x), altitude is x so substitute. Now we know the area of a triangle is base X height X 1/2. Substitute again! 1/2 (3+x)(x)=35. Multiply both sides by 2 to cancel out the 1/2. Now you have (x)(x+3)=70 and you have to foil out the left side x^2+3x=70. Subtract 70 on both sides x^2+3x-70=0. Find two numbers that multiply to -70 and add to 3. Solve (x+10)(x-7)=0. the x value is 7. since you can't have negative length values. Substitute 7 into 3+x for the base so you know the base is 10 and the height is 7.

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Find the discriminant for the following equation 3x^2+4x=2
hichkok12 [17]

Answer:

The discriminant is 40

Step-by-step explanation:

First, rewrite the equation as 3x^2+4x-2=0 so that the equation is in the form of ax^2+bx+c=0. Thus, the discriminant is b^2-4ac=(4)^2-4(3)(-2)=16+24=40. This tells us that since the discriminant is greater than 0, then there are 2 real solutions.

6 0
3 years ago
Read 2 more answers
Find the 7th term of the geometric sequence a3 =128,r=-1/4
kenny6666 [7]

Answer:

Step-by-step explanation:

The general formula for this sequence is a(n) = a(1)*(-1/4)^(n - 1).  We don't yet know a(1).

If a(3) = 128, then 128 = a(1)*(-1/4)^(3 - 1), or

128 = a(1)*(1/16)

and so a(1) = 128/16

resulting in the specific formua a(n) = 8(-1/4)^(n - 1)

Now let's find a(7):

a(7) = 8(-1/4)^1 * (-1/4)^(6)

or

a(7) = 8(-1/4)^7

7 0
4 years ago
Which pair of functions have the same domain? A. F(x)= sin x and g(x) = tan x B. F(x) = cos x and f(x) = csc x C. G(x) = tan x a
EastWind [94]

Answer:

The correct choice is D

Step-by-step explanation:

The trigonometric functions, \sin x and \cos x are defined for all real numbers.

\tan x=\frac{\sin x}{\cos (x)}, this function is not defined where \cos x=0.

\cot x=\frac{\cos x}{\sin (x)}, this function is not defined where \sin x=0.

\csc x=\frac{1}{\sin (x)}, this function is not defined where \sin x=0.

For option A

The domain of f(x)=\sin(x) is all real numbers.

The domain of g(x) =tanx is x\ne \frac{(2n+1)\pi}{2}

For option B

The domain of f(x)=\cos(x) is all real numbers.

The domain of f(x) =csc(x) is x\ne n\pi

For option C,

The domain of G(x) =tanx is x\ne \frac{(2n+1)\pi}{2}

The domain of f(x) =cot(x) is x\ne n\pi

For option D;

The domain of f(x) =cot(x) is x\ne n\pi

The domain of f(x) =csc(x) is x\ne n\pi

3 0
4 years ago
Read 2 more answers
A line has a slope of -3 and y-intercept of 2.
Pie

AnswA line can be written in the form y = mx + b where m is the slope and b is the y intercept.

Since the slope is given as 4, the equation will be y = 4x + b

Plugging in the point (2,1) to the equation we get 1 = 4(2) + b or 1 = b + 8

Solving for b gives b = -7 so the equation will be y = 4x - 7er:

Step-by-step explanation:

5 0
3 years ago
Write an expression that evaluates to true if the int associated with number_of_prizes is divisible (with no remainder) by the i
hodyreva [135]

We need to find the expression for " number_of_prizes is divisible number_of_participants". Also there should not remain any remainder left. On in order words, we can say the reaminder we get after division is 0.

Let us assume number of Prizes are = p and

Number of participants = n.

If we divide number of Prizes by number of participants and there will be not remainder then there would be some quotient remaining and that quotent would be a whole number.

Let us assume that quotent is taken by q.

So, we can setup an expression now.

Let us rephrase the statement .

" Number of Prizes ÷ Number of participants  = quotient".

p ÷ n = q.

In fraction form we can write

p/n =q   ; n ≠ 0.


4 0
3 years ago
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