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Anna11 [10]
3 years ago
5

Which models can be used to solve the problem

Mathematics
2 answers:
otez555 [7]3 years ago
8 0
The fourth one is your answer ty
victus00 [196]3 years ago
4 0
The 4th one
The 4th one
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Look at the sets below.
ahrayia [7]

Answer:

Answer is A

A contains all the elememts common to both the sets and thus it is the inteesection of the given two sets.

I hope this helps you

#Indian : )

6 0
3 years ago
Please help soon- The weight of oranges growing in an orchard is normally distributed with a mean
Leya [2.2K]
5 oz. Hope this helped!
5 0
3 years ago
WHERE DID CAROLYN MESS UP?
Anuta_ua [19.1K]

Answer:

line 2 of her working

Step-by-step explanation:

when multiplying the brackets out it is a negative times posative so she should have wrote -4 not +4

6 0
3 years ago
A direct variation function includes the ordered pair (4, 5). Which statement is true? The constant of variation k is mc001-1.jp
devlian [24]
A direct variation suggest that the value of x in the equation would greatly affect the value of y such that when x is increasing, y also increases and the other way around. The equation for a direct variation is that,
                               y  = kx
Substituting the given values in the ordered pair,
                           5 = k(4)   ; k = 5/4
7 0
3 years ago
Read 2 more answers
Slips of paper numbered 1 to 15 are placed in a box. A slip of paper is drawn at random. What is the probability that the number
monitta

Given:

Slips of paper numbered 1 to 15 are placed in a box.

To find:

The probability that the number picked is either a multiple of 5 or an odd number.

Solution:

We have,

Total outcomes = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15

No. of total outcomes = 15

Multiple of 5 are 5, 10, 15.

Odd numbers are 1, 3, 5, 7, 9, 11, 13, 15.

Number that are either a multiple of 5 or an odd number are 1, 3, 5, 7, 9, 10, 11, 13, 15.

No. of favorable outcomes = 9

We know that,

\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

\text{Probability}=\dfrac{9}{15}

\text{Probability}=\dfrac{3}{5}

\text{Probability}=0.6

Therefore, the  probability that the number picked is either a multiple of 5 or an odd number is 0.6.

8 0
3 years ago
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