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4 years ago

Which models can be used to solve the problem

Mathematics

2 answers:

otez555 [7]4 years ago

8 0

The fourth one is your answer ty

victus00 [196]4 years ago

4 0

The 4th one
The 4th one

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Y-1= -3(x + 4)<br><br> Find the equation for y

sineoko [7]

Y=-3x-11. you add the one to the other side making the equation y=-3(x+4)+1
then you distribute making it y=-3x-12+1

8 0

3 years ago

Read 2 more answers

I need help please!!!

e-lub [12.9K]

There is no distinct pattern, the scatter plot would be up down and spread apart, nothing really correlated.

3 0

3 years ago

12,108 round to nearest thousand

Shalnov [3]

The answer is 12,000 because the 1(00) was not enough to raise it to 13,000.

12,502 would round to 13,000

The answer to your question is 12,000

7 0

3 years ago

In a certain liberal arts college with about 10,000 students, 53% are males. If two students from this college are selected at r

tamaranim1 [39]

Answer:

There is a 50.18% probability that they are of the same gender.

Step-by-step explanation:

We have these following percentages:

53% of the students are males.

47% of the students are females.

If two students from this college are selected at random, what is the probability that they are of the same gender?

The probability that each is male is 53%. So the probability of both being males is

$P_{MM} = 0.53*0.53 = 0.2809$

The probability that each is female is 47%. So the probability of both being females is

$P_{FF} = 0.47*0.47 = 0.2209$

The probabilty that both are the same gender is:

$P = P_{MM} + P_{FF} = 0.2809 + 0.2209 = 0.5018$

There is a 50.18% probability that they are of the same gender.

7 0

4 years ago

The following random sample was selected from a normal distribution: 4.5, 6.4, 2.3, 1.8, 5.3, then the 95% confidence interval t

kap26 [50]

Answer:

the 95% confidence interval to estimate the population mean is between 1.62 and 6.50

Step-by-step explanation:

given data

distribution = 4.5, 6.4, 2.3, 1.8, 5.3

so n = 5

confidence interval = 95%

to find out

the population mean is between

solution

first we calculate the mean i.e.

mean = $\frac{1}{n}\sum_{i=1}^{n}x(i)$

mean = 4.5+ 6.4+ 2.3+ 1.8+ 5.3 / 5

mean = 4.06

now we calculate the standard deviation i.e.

standard deviation = $\sqrt{\frac{1}{n-1}\sum (x(i)-mean)^2}$

standard deviation = $\sqrt{\frac{1}{5-1}\sum (x(i)-mean)^2}$

standard deviation = $\sqrt{\frac{1}{5-1} (4.5-5)^2+(6.4-5)^2 +(2.3-5)^2+(1.8-5)^2+(5.3-5)^2}$

standard deviation = $\sqrt{\frac{1}{4} (4.5-5)^2+(6.4-5)^2 +(2.3-5)^2+(1.8-5)^2+(5.3-5)^2}$

standard deviation = 2.226544

so 95 % confidence interval is i.e. mean +/- t(5) * standard deviation/ $\sqrt{n}$

here t(5) will be 2.45

95 % confidence interval= 4.06 +/- 2.45 * 2.226 / $\sqrt{5}$

95 % confidence interval= 1.62 and 6.50

4 0

3 years ago