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3 years ago

If all the demsions pf a 1 foot cube are doubled what is the area of its label

Mathematics

1 answer:

Pavel [41]3 years ago

6 0

4 ft because if there all doubled it means there all two and area is length times width so 2 times 2 is 4

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Solve using substitution.<br> y = -x - 1<br> y = x + 3<br> Submit

Alex Ar [27]

Answer:

Step-by-step explanation:

-x - 1 = x + 3

-2x - 1 = 3

-2x = 4

x = -2

y = -2 + 3

y = 1

(-2, 1)

4 0

3 years ago

Please answer and show a little work

Pavlova-9 [17]

1 kilometer = 1000 meters

3 kilometers would be 3000 meters

Divide total meters by number of parcels:

3000 / 10 = 300

The answer is 300 meters

5 0

3 years ago

Please help > _ < Show your work and eplain

san4es73 [151]

Alternate exterior means opposite sides of the transversal and outside the parallel lines... angles 1, 2, 5, 6 are all outside the parallel lines.. now you just need to match up the ones that are on opposite sides... 1 and 5 are opposite sides and 2 and 6 are opposite sides.. so those two pairs are the alternate exterior angles.. since 2 and 6 isn't a choice and 1 and 5 is, then there is your answer.

8 0

3 years ago

Determine whether angle ABC should be solved by using the Law of Sines or the Law of Cosines. Then solve the triangle.

drek231 [11]

Answer:

Law of Cosines

Angle A = 45°

Angle B = 51°

Angle C = 84°

Step-by-step explanation:

Law of sines is used when we are given

a) two angles and one side or

b) two sides and non-included angle

Law of cosines is used when we are given

a) three sides or

b) two sides and included angle

In the given question we are given three sides so, Law of Cosines will be used to solve the triangle.

Law of Cosines is:

$a^2 = b^2 + c^2 -2bccos A\\b^2 = a^2 + c^2 -2accos B\\c^2 = a^2 + b^2 -2abcosC$

We will find the three angles A ,B and C of the triangle using above formula.

a= 10, b=11, c=14

Putting values and finding angle A

$a^2 = b^2 + c^2 -2bccos A\\(10)^2 = (11)^2 + (14)^2 -2(11)(14)cosA\\100 = 121 + 196 -308cosA\\100 = 317 -308 cosA\\100-317 = -308cosA\\-217/-308 = cos A\\0.704 = cos A\\=> A = cos ^{-1}(0.704)\\A= 45$

Now finding angle B

$b^2 = a^2 + c^2 -2ac cos B\\(11)^2 = (10)^2 + (14)^2 - 2(10)(14)cosB\\121 = 100+196 - 280cosB\\121 -296 = -280cosB\\-175/-280 = cosB\\0.625 = cosB\\=> B = cos^{-1} (0.625)\\B = 51$

Now finding angle C

$c^2 = a^2 + b^2 -2abcosC\\(14)^2 =(10)^2 + (11)^2 -2(10)(11)cosC\\196 = 100+121 -220cosC\\196 -221 = -220cosC\\-25/-220 = cos C\\0.11 = cosC\\=> C = cos^{-1}(0.11)\\C= 84$

4 0

3 years ago

Read 2 more answers

Find 2 values for x for which f(x)=-28

Mekhanik [1.2K]

-7 x 4= -28

-14 x 2+ 28

8 0

3 years ago