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zloy xaker [14]
3 years ago
10

Jessica is filling her swimming pool with water. The pool will hold 500 gallons of water,

Mathematics
1 answer:
Gre4nikov [31]3 years ago
4 0
Hey hey y’all is that the answer
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Share £747 in the ratio 2:7
ivanzaharov [21]
Ratio: 2:7
2+7 = 9

747 / 9 = 83

83*2 = 166

83 * 7 = 581

166 to 581
5 0
3 years ago
Read 2 more answers
Your having lunch at Taco Bell. You have your choice of a taco,burrito or Mexican pizza. You can choose between rice and beans.
tino4ka555 [31]

Let T be the taco, B the burrito, MP the mexican pizza, R the rice, and N the beans.

For the main course we can have the first three.

----- T

------ B

-------MP

Each main course comes with the two sides. So an R branch and a B branch go to each of the taco, burrito, or pizza.

-----T---------R or N.

We expand it to

--------T-----------R

---------------------N

And we repeat it for the rest.


Thus, the tree diagram is

----- T --------R

-----------------N

-----B---------R

-----------------N

----MP--------R

----------------N

5 0
3 years ago
Read 2 more answers
A phone company offers two monthly plans. Plan A costs $10 plus an additional $0.15 for each minute of calls. Plan B costs $30 p
Mkey [24]

First, you need to write to expressions to model each situation:

Plan A: 10+0.15x

Plan B: 30+0.1x


Next, set the expressions equal to each other and solve for x:

10+0.15x=30+0.1x

<em>*Subtract 0.1x from both sides to isolate the variable*</em>

10+0.05x=30

<em>*Subtract 10 from both sides*</em>

0.05x=20

<em>*Divide both sides by 0.05*</em>

x=400


The plans would have the same cost after 400 minutes of calls.


To find how much money the plans cost at 400 minutes, plug 400 into either expression.  We'll use Plan A:

10+0.15(400)

10+60

70


The plans will cost $70.


Hope this helps!

3 0
3 years ago
What is the common difference between the elements of the arithmetic sequence below?
daser333 [38]
-4.5 might be the answer im not very sure but yeah
5 0
3 years ago
Read 2 more answers
2. A solar lease customer built up an excess of 6,500 kilowatt hours (kwh) during the summer using his solar
tia_tia [17]

9514 1404 393

Answer:

  a)  E = 6500 -50d

  b)  5000 kWh

  c)  the excess will last only 130 days, not enough for 5 months

Step-by-step explanation:

<u>Given</u>:

  starting excess (E): 6500 kWh

  usage: 50 kWh/day (d)

<u>Find</u>:

  a) E(d)

  b) E(30)

  c) E(150)

<u>Solution</u>:

a) The exces is linearly decreasing with the number of days, so we have ...

  E(d) = 6500 -50d

__

b) After 30 days, the excess remaining is ...

  E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days

__

c) After 150 days, the excess remaining would be ...

  E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system

The supply is not enough to last for 5 months.

3 0
3 years ago
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