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Solnce55 [7]
3 years ago
9

Need within the next 15 min PLEASE!!​

Mathematics
1 answer:
Vadim26 [7]3 years ago
7 0

The value of \log _{4} 1 is 0.

Explanation:

The expression is \log _{4} 1

Now, we shall find the value of \log _{4} 1

Let us apply the log rule : \log _{a}(1)=0

This means that the logarithm of 1 is always zero regardless of the base of the logarithm. This is because, we know that any number whose power is zero always equal to one.

Since , the expression is of the form \log _{a}(1), we have,

\log _{4} 1=0

Thus, the value of \log _{4} 1 is 0.

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Which expression is equivalent to 11 - (-3 5/8)?
anyanavicka [17]

Answer:

11 - (-3 5/8)

= 11 + 3 5/8 ( 2 negative signs become positive)

answer is B.11 + 3 5/8

Step-by-step explanation:

5 0
3 years ago
Please Help??
SOVA2 [1]
Well, if you notice, is just an arithmetic sequence, is adding 2 to get the next term.

so the last term is 21, so the one before that has to be 21-2 or 19, and the one before that 17 and the one before that 15.

15+17+19+21.
4 0
3 years ago
REF<br> What is the greatest common factor of 35x6 and 7x2?
IRINA_888 [86]
14 is the greatest common factor
6 0
4 years ago
A positive angle less than 360 degrees that is coterminal with -5 degrees is
nadya68 [22]

Answer:

\theta = 355

Step-by-step explanation:

Given

Let the angle be \theta

\theta < 360

\theta is co-terminal with -5

Required

Find \theta

Start by dividing 5 by 360 (ignore the negative)

\frac{5}{360} = 0.0138

The nearest integer greater than 0.0138 is 1.

<em>This implies that if you were to draw for this problem, the circle you would draw to show -5 degrees would go around 1 time</em>

So, \theta is calculated as:

\theta = -5 + 1*360

\theta = -5 +360

\theta = 355

7 0
3 years ago
The ages of 11 students enrolled in an on-line macroeconomics course are given in the following steam-and-leaf display:
blsea [12.9K]

Answer:

The standard deviation of the age distribution is 6.2899 years.

Step-by-step explanation:

The formula to compute the standard deviation is:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

The data provided is:

X = {19, 19, 21, 25, 25, 28, 29, 30, 31, 32, 40}

Compute the mean of the data as follows:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}

  =\frac{1}{11}\times [19+19+21+...+40]\\\\=\frac{299}{11}\\\\=27.182

Compute the standard deviation as follows:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

      =\sqrt{\frac{1}{11-1}\times [(19-27.182)^{2}+(19-27.182)^{2}+...+(40-27.182)^{2}]}}\\\\=\sqrt{\frac{395.6364}{10}}\\\\=6.28996\\\\\approx 6.2899

Thus, the standard deviation of the age distribution is 6.2899 years.

7 0
3 years ago
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