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timurjin [86]
3 years ago
8

Will mark brainliest hi! Pls answer only if you know <3

Mathematics
1 answer:
Shtirlitz [24]3 years ago
3 0

Answer:

(6, - 1 )

Step-by-step explanation:

Given the 2 equations

2x + y = 11 → (1)

\frac{1}{2} x - 5y = 8 ← (2)

Multiplying (2) by - 4 and adding to (1) will eliminate the x- term

- 2x + 20y = - 32 → (3)

Add (1) and (3) to eliminate x

0 + 21y = - 21

21y = - 21 ( divide both sides by 21 )

y = - 1

Substitute y = - 1 into either of the 2 equations and solve for x

Substituting into (1)

2x - 1 = 11 ( add 1 to both sides )

2x = 12 ( divide both sides by 2 )

x = 6

solution is (6, - 1 )

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Write the fraction or mixed number as a percent.<br><br> 9/25
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36%

Step-by-step explanation:

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ANSWER THIS PLZZZZZZ
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The gross income of David Vaughn is $785 per week. His deductions are $42.25, FICA tax; $90.33, income tax; 2% state tax; 1% cit
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4 years ago
Construct the indicated confidence interval for the difference in proportions. Assume that the samples are independent and that
IceJOKER [234]

Answer:

CI 99%   =  ( - 0.0009 ;  0.0541 )

Step-by-step explanation:

Sample 1 New Yorkers

sample size    n₁   =  558

x₁  =  193

p₁ = x₁/n₁   =  193/ 558      p₁ =  0.3458  q₁ =  1  - p₁   q₁  =  1  -  0.3458

q₁  =  0.6542

Sample 2  Californians

sample size     n₂  =  614

x₂  =  196

p₂  =  x₂/n₂  =  196 / 614    p₂ = 0.3192   q₂  =  1  -  p₂   q₂ =  1 - 0.3192

q₂ =  0.6808

CI 99 %    means   significance level α  = 1 αα%    α = 0.01

α/2  =  0.005

In z-table we look for z score for  0.005    z (c) =  2.57

CI 99 %  =  [  (  p₁  -  p₂ ) ±  z(c) * √( p₁*q₁)/n₁  + ( p₂*q₂)/n₂

p₁ - p₂  =  ( 0.3458 - 0.3192 )  =  0.0266

√( p₁*q₁)/n₁  + ( p₂*q₂)/n₂   =√  0.3458*0.6542)/558 +  0.3192*0.6808)/614

√( p₁*q₁)/n₁  + ( p₂*q₂)/n₂   = √ 4.05*10⁻⁴   +  3.54 * 10⁻⁴

√( p₁*q₁)/n₁  + ( p₂*q₂)/n₂   =  10⁻² * √7.59    =  10⁻²  *  2.75

Then:

CI 99 %  =  0.0266  ±  2.75 * 10⁻²

CI 99%   =  0.0266   ±  0.0275

CI 99%   =  ( - 0.0009 ;  0.0541 )

6 0
3 years ago
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