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tamaranim1 [39]
3 years ago
7

How much will it cost guys

Mathematics
2 answers:
aalyn [17]3 years ago
8 0

Answer:

635 pounds hope you do good :)

Step-by-step explanation:


34kurt3 years ago
6 0

Answer:


Step-by-step explanation:

I would say probably 695E.The reason why I said that answer is because 30*2 equals 60.Then it took a additional 12 minutes and I know that 12*5 equals 60 so I divided 30 by 5.I got 6 and added it to 60 which got me 66.Then I multiplied that by 10.After that I just added the 35 to it.

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Y=5x-1 and -15x-3y=3 how many solutions does this have
Artemon [7]
No solutions. The equation would be
-15x-3(5x-1)=3
-15x-15x-3=3
No Solution

Hope this helped?
4 0
3 years ago
Mrs cousins works in a pool store and earns a 9.5% commission on every swimming pool she sells. how much commission did she earn
Dennis_Churaev [7]
She earned $532 for selling the pool
7 0
3 years ago
The product of -2 and a number minus 6 is greater than -18
Eduardwww [97]
So product means multiplication so -2*(x-6) > -18 so divide by -2 on both sides to get x-6<9 because when you multiply a negative the sign swaps directions and then add 6 to get x<15
8 0
3 years ago
During the spring and summer months, the Happy Home Motel sees a rise in travelers. The manager of the motel turned in this repo
Korvikt [17]

Answer:

342

Step-by-step explanation:

Let's see the difference is each successive values:

232 - 217 = 15

252 - 232 = 20

277 - 252 = 25

307 - 277 = 30

As we can see, each month the increase is 5 more than previous months' increase. <em>Clearly from the pattern we can surmise that the next month (August), it will increase by 35 from the value of July.</em>

Number of visitors in August = Number of Visitors in  July + 35 = 307 + 35 = 342

4 0
3 years ago
Read 2 more answers
The plane x + y + z = 12 intersects paraboloid z = x^2 + y^2 in an ellipse.(a) Find the highest and the lowest points on the ell
emmasim [6.3K]

Answer:

a)

Highest (-3,-3)

Lowest (2,2)

b)

Farthest (-3,-3)

Closest (2,2)

Step-by-step explanation:

To solve this problem we will be using Lagrange multipliers.

a)

Let us find out first the restriction, which is the projection of the intersection on the XY-plane.

From x+y+z=12 we get z=12-x-y and replace this in the equation of the paraboloid:

\bf 12-x-y=x^2+y^2\Rightarrow x^2+y^2+x+y=12

completing the squares:

\bf x^2+y^2+x+y=12\Rightarrow (x+1/2)^2-1/4+(y+1/2)^2-1/4=12\Rightarrow\\\\\Rightarrow (x+1/2)^2+(y+1/2)^2=12+1/2\Rightarrow (x+1/2)^2+(y+1/2)^2=25/2

and we want the maximum and minimum of the paraboloid when (x,y) varies on the circumference we just found. That is, we want the maximum and minimum of  

\bf f(x,y)=x^2+y^2

subject to the constraint

\bf g(x,y)=(x+1/2)^2+(y+1/2)^2-25/2=0

Now we have

\bf \nabla f=(\displaystyle\frac{\partial f}{\partial x},\displaystyle\frac{\partial f}{\partial y})=(2x,2y)\\\\\nabla g=(\displaystyle\frac{\partial g}{\partial x},\displaystyle\frac{\partial g}{\partial y})=(2x+1,2y+1)

Let \bf \lambda be the Lagrange multiplier.

The maximum and minimum must occur at points where

\bf \nabla f=\lambda\nabla g

that is,

\bf (2x,2y)=\lambda(2x+1,2y+1)\Rightarrow 2x=\lambda (2x+1)\;,2y=\lambda (2y+1)

we can assume (x,y)≠ (-1/2, -1/2) since that point is not in the restriction, so

\bf \lambda=\displaystyle\frac{2x}{(2x+1)} \;,\lambda=\displaystyle\frac{2y}{(2y+1)}\Rightarrow \displaystyle\frac{2x}{(2x+1)}=\displaystyle\frac{2y}{(2y+1)}\Rightarrow\\\\\Rightarrow 2x(2y+1)=2y(2x+1)\Rightarrow 4xy+2x=4xy+2y\Rightarrow\\\\\Rightarrow x=y

Replacing in the constraint

\bf (x+1/2)^2+(x+1/2)^2-25/2=0\Rightarrow (x+1/2)^2=25/4\Rightarrow\\\\\Rightarrow |x+1/2|=5/2

from this we get

<em>x=-1/2 + 5/2 = 2 or x = -1/2 - 5/2 = -3 </em>

<em> </em>

and the candidates for maximum and minimum are (2,2) and (-3,-3).

Replacing these values in f, we see that

f(-3,-3) = 9+9 = 18 is the maximum and

f(2,2) = 4+4 = 8 is the minimum

b)

Since the square of the distance from any given point (x,y) on the paraboloid to (0,0) is f(x,y) itself, the maximum and minimum of the distance are reached at the points we just found.

We have then,

(-3,-3) is the farthest from the origin

(2,2) is the closest to the origin.

3 0
3 years ago
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