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horrorfan [7]
3 years ago
15

Please select the best answer from the choices provided

Mathematics
2 answers:
NeTakaya3 years ago
8 0

we are given

2^{\frac{1}{2}}\cdot 2^{\frac{1}{2} }

we can use exponent formula

a^n \cdot a^m=a^{n+m}

now, we can use this formula

2^{\frac{1}{2}}\cdot 2^{\frac{1}{2} }=2^{\frac{1}{2}+\frac{1}{2} }

we can add exponent

and we get

2^{\frac{1}{2}}\cdot 2^{\frac{1}{2} }=2^{\frac{1+1}{2} }

2^{\frac{1}{2}}\cdot 2^{\frac{1}{2} }=2^{\frac{2}{2} }

2^{\frac{1}{2}}\cdot 2^{\frac{1}{2} }=2^{1}

2^{\frac{1}{2}}\cdot 2^{\frac{1}{2} }=2

So, option-B.......Answer

docker41 [41]3 years ago
8 0

<u>Answer:</u>

The correct answer option is b. 2.

<u>Step-by-step explanation:</u>

We are given an expression 2^{\frac{1}{2}  }.2^{\frac{1}{2}  } and we are supposed to simplify it.

We know that a^b.a^c= a^{b+c} which means if the bases are same, then the exponents are added up.

So here, our bases are same i.e. 2 so we will add up the exponents to get:

2^{\frac{1}{2}+ \frac{1}{2}  }

Taking the LMC of the exponents to get:

2^{\frac{1+1}{4}  }

2^{\frac{2}{2}  }

The fraction in the exponent gets cancelled so we are left with 2.

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[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
4 years ago
Glenn invested $15,000 at 3% interest compounded annually.
Anestetic [448]

15000 * (1+ 0.03)^4

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16882.63 - 15000 = 1882.63 total interest


Answer is D


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3 years ago
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Answer:

c

Step-by-step explanation:

x*x=x^2

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6 0
3 years ago
Read 2 more answers
May I have some help?
chubhunter [2.5K]
For whatcha problem hun
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Will mark Brainliest!!!<br> Try to show a little work!❤️❤️❤️❤️❤️❤️❤️
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Answer:

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