Answer: the fractional increase is 1/5
Step-by-step explanation:
The initial area of Julio's living room was 1000 sq. ft. Then he added a room that was 20 ft. by 10 ft. The area of the room that was added to the living room would be
20 × 10 = 200 square feet
The new area of the room would be
1000 + 200 = 1200 square feet
Therefore, the fractional increase of the living space would be
Increase in area/original area
It becomes
200/1000 = 1/5
B is true because the second graph has a lower average
from 1, to 3, to 5 to 7, notice, is simply adding 2 to get the next term.
1+2 =3, 3+2 =5 and so on.
so the common difference is 2, and the first term is of course 1.
![\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=1\\ d=2\\ n=24 \end{cases} \\\\\\ a_{24}=1+(24-1)2\implies a_{24}=1+(23)2\implies a_{24}=1+46\implies a_{24}=47](https://tex.z-dn.net/?f=%5Cbf%20n%5E%7Bth%7D%5Ctextit%7B%20term%20of%20an%20arithmetic%20sequence%7D%0A%5C%5C%5C%5C%0Aa_n%3Da_1%2B%28n-1%29d%5Cqquad%0A%5Cbegin%7Bcases%7D%0An%3Dn%5E%7Bth%7D%5C%20term%5C%5C%0Aa_1%3D%5Ctextit%7Bfirst%20term%27s%20value%7D%5C%5C%0Ad%3D%5Ctextit%7Bcommon%20difference%7D%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa_1%3D1%5C%5C%0Ad%3D2%5C%5C%0An%3D24%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0Aa_%7B24%7D%3D1%2B%2824-1%292%5Cimplies%20a_%7B24%7D%3D1%2B%2823%292%5Cimplies%20a_%7B24%7D%3D1%2B46%5Cimplies%20a_%7B24%7D%3D47)
Tried my best here, but sorry if they are wrong
2. 15r - 7j
3. 4b - 2n
4. 12g - 4g = 8g
5. 8c - 5
6. 2(2b + 6j)
7. 3(2s - 5f)
8. 10c + s + 2p
9. 2a <3p
10. 5(a+b)
11. 1/2r + 3/4g
12. 10(b * f)
the answer is b Im pretty sure
