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3 years ago

5

The scatterplot shows the number of athletes on the field hockey and tennis teams at Southern High School during seven different

years. Which statement is best supported by the line of best fit?
When there are 65 field hockey players, there will be about 40 tennis players.

When there are 20 field hockey players, there will be about 20 tennis players.

When there are 10 field hockey players, there will be about 35 tennis players.

When there are 40 field hockey players, there will be about 25 tennis players.

2 answers:

Natasha_Volkova [10]3 years ago

6 0

Answer:

When there are 10 field hockey players, there will be about 35 tennis players.

Step-by-step explanation:

i took the test

kykrilka [37]3 years ago

5 0

Answer:

c

Step-by-step explanation:

edge 2020

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PLEASE HELP I WILL GIVE BRAINLIEST!!!!!!

Natasha2012 [34]

Answer:

3rd answer EF = 2√13

Step-by-step explanation:

Make a right triangle and use Pythagorean theorem a²+b² = c²

Go from point F 6 units down till point (1,-3) .From that point go 4 units left till you hit point E.

Triangle has legs a and b that are 6 and 4 units long so 6² + 4² = EF²

36 + 16 = 52

EF² = 52 find √52

EF = √52

There is no √52 as a whole number so rewrite 52 as a product of number who was a √ and the other who doesn't have a √

52 = 4 * 13

EF = √4 * √13 = 2√13

3 0

2 years ago

Jordan needs one can of juice to make 24 servings of a punch. How many servings of punch can she make with 1/2 a can of juice?

kati45 [8]

Compare the two sets of numbers with a ratio. 1 can for 24 servings is to 1/2 can for x servings.

x= # servings from 1/2 can

1/24= (1/2)/x
cross multiply

1 * x= 24 * 1/2

x= 24/2

x= 12 servings

ANSWER: She can make 12 servings from 1/2 can of juice.

Hope this helps! :)

3 0

3 years ago

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

5 0

3 years ago

The questions are in the pic the other answer is 356

Andru [333]

The answer to this question is 356

4 0

3 years ago

Please help mepleaseeeeeeeeeeeeeeeeeeeeeee

goblinko [34]

Answer:

Both are Obtuse Angles

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers