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sdas [7]
3 years ago
9

Select the description that is true of the equation y=-5x+5 .

Mathematics
1 answer:
gladu [14]3 years ago
3 0
In y = mx + b form, the slope is in the m position and the y intercept is in the b position.

y = (m)x + (b)
y = -5  x  + 5.....slope (m position) = -5....y int (b position) = 5
You might be interested in
One number is 4 times as large another. The sum of their reciprocals is 45/4. Find the two numbers
Reptile [31]
Let, 
the numbers be "x" and "y"
According to the question,
x = 4y ......................................................equation (1)

\frac{1}{x} + \frac{1}{y}= \frac{45}{4}...................................equation (2)

Taking equation (2)
\frac{1}{x} + \frac{1}{y}= \frac{45}{4}

Substituting the value of "x" from equation (1), we get,

\frac{1}{(4y)} + \frac{1}{y}= \frac{45}{4}

\frac{1}{4y} + \frac{1}{y}* \frac{4}{4} = \frac{45}{4}

\frac{1}{4y} + \frac{4}{4y}= \frac{45}{4}

\frac{1+4}{4y} = \frac{45}{4}

\frac{5}{4y} = \frac{45}{4}

Cross multiplying, we get,

5*4 = 45*4y

20 = 180y
<u />
\frac{20}{180}  = y

\frac{1}{9}  = y

y =  \frac{1}{9}

Now,
Taking equation (1)
x = 4y
Substituting the value of "y", we get

x = 4( \frac{1}{9} )

x= \frac{4}{9}

So, the numbers are \frac{1}{9} and \frac{4}{9}

7 0
2 years ago
Read 2 more answers
Let f(x)=2.912345x^2+3.131579x-0.099999
Rudiy27
A.) Integers are positive and negative counting numbers. So, in order to find the integer coefficients, round off the coefficients in the equation to the nearest whole number. The function for g(x) is:

g(x) = 3x²+3x

B.) Substitute x=4 to the two functions.

f(x) = 2.912345x²<span>+3.131579x-0.099999
</span>f(4) = 2.912345(4)²+3.131579(4)-0.099999
f(4) = 59.023837

g(x) = 3x²+3x
g(4) = 3(4)²+3(4)
g(4) = 60

C.) The percentage error is equal to:

Percentage error = |g(4) - f(4)|/f(4)  * 100
Percentage error = |60 - 59.023837|/59.023837  * 100
Percentage error = 1.65%

D.) If x is a large number, for example x=10 or x=20, then g(x) would be an overestimate. This is because the value of x is raised to the power of 2. So, as the x increases, the corresponding function would increase exponentially. Even at x=4, g(x) is already an overestimate. What more for larger values of x? That means that the gap from the true answer f(x) would increase.
5 0
3 years ago
If you bought a stock last year for a price of $124, and it has gone down 5.6% since then, how much is the stock worth now, TO T
pychu [463]

Answer:

124*0.9=111.6

Step-by-step explanation:


6 0
3 years ago
Please help me please !
Morgarella [4.7K]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

Option C

»»————- ★ ————-««  

Here’s why:

⸻⸻⸻⸻  

\text{\underline{The Slope Formula Is:}}\\\\m=\frac{y_2-y_1}{x_2-x_1}\\\\(x_1,y_1)\text{ and } (x_2,y_2)\text{ are two points given.}\\\\\text{We are given the points: } (3,5) \text{ and } (9,2).\\\\\text{\underline{The formula for the points should be:}}\\\\m=\frac{5-2}{3-9}, \text{where } (9,2) \text{ is }(x_1,y_1)\text{ and } (3,5) \text{ is } (x_2,y_2).

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

7 0
3 years ago
How do I solve the equation in an interval from 0 to 2π ? 9 cos 2t = 6​
Ivahew [28]

9\cos(2t)=6\implies\cos(2t)=\dfrac23

Using the fact that cos is 2π-periodic, we have

\cos(2t)=\dfrac23\implies2t=\cos^{-1}\left(\dfrac23\right)+2n\pi

That is, \cos(\theta+2n\pi)=\cos\theta for any \theta and integer n.

\implies t=\dfrac12\cos^{-1}\left(\dfrac23\right)+n\pi

We get 2 solutions in the interval [0, 2π] for n=0 and n=1,

t=\dfrac12\cos^{-1}\left(\dfrac23\right)\text{ and }t=\dfrac12\cos^{-1}\left(\dfrac23\right)+\pi

4 0
2 years ago
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