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sdas [7]
3 years ago
9

Select the description that is true of the equation y=-5x+5 .

Mathematics
1 answer:
gladu [14]3 years ago
3 0
In y = mx + b form, the slope is in the m position and the y intercept is in the b position.

y = (m)x + (b)
y = -5  x  + 5.....slope (m position) = -5....y int (b position) = 5
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Which pairs of angles in the figure below are vertical angles?<br> Check all that apply.
solmaris [256]

Answer:

A. and D.

Step-by-step explanation:

6 0
3 years ago
Give the exponential function A(x)=P(1+r)x, what value for r will make the function a growth function?
wolverine [178]

for this to be a growth function it has to be any number that is latger than zero

FOR EXAMPLE :-

50% which equals to 0.5

4 0
3 years ago
You are designing a rectangular garden. the garden will be enclosed by fencing on three sides and by a house on the fourth side.
RUDIKE [14]
Suppose the dimensions of the rectangle is x by y and let the side enclosed by a house be one of the sides measuring x, then the sides that is to be enclosed are two sides measuring y and one side measuring x.

Thus, the length of fencing needed is given by

P = x + 2y

The area of the rectangle is given by xy,

i.e.

xy = 288  \\  \\  \\  \\ \Rightarrow y= \frac{288}{x}

Substituting for y into the equation for the length of fencing needed, we have

P=x+2\left( \frac{288}{x} \right)=x+ \frac{576}{x}

For the amount of fencing to be minimum, then

\frac{dP}{dx} =0 \\  \\ \Rightarrow1- \frac{576}{x^2} =0 \\  \\ \Rightarrow \frac{576}{x^2} =1 \\  \\ \Rightarrow x^2=576 \\  \\ \Rightarrow x=\sqrt{576}=24

Now, recall that

y= \frac{288}{x} = \frac{288}{24} =12

Thus, the length of fencing needed is given by

P = x + 2y = 24 + 2(12) = 24 + 24 = 48.

Therefore, 48 feets of fencing is needed to enclose the garden.
8 0
3 years ago
1/2(8x-6) = x + 9 solve ... hurry
QveST [7]

Answer:

x=4

Step-by-step explanation:

4x-3=x+9

4x-x-3=9

4x-x=9+3

3x=9+3

3x=12

3/3

12/3=4

x=4

5 0
3 years ago
Read 2 more answers
#54 Simplify and write the answers using positive exponents only.
kramer
Gg easy

remember
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
(xyz)^m=(x^m)(y^m)(z^m)
and
(m/n)^a=(m^a)/(n^a)
and
x^-n=1/(x^n)

so
( \frac{6mn^{-2}}{3m^{-1}n^2} )^{-3}=
( \frac{6}{3} )^{-3}( \frac{m}{m^{-1}} )^{-3}( \frac{n^{-2}}{n^2} )^{-3}=
(2^{-3})((m^2)^{-3})((n^{-4})^{-3})=
( \frac{1}{2^3})(m^{-6})(n^{12})=
( \frac{1}{8} )( \frac{1}{m^6})(n^{12})=
\frac{n^{12}}{8m^6}

8 0
4 years ago
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