Answer: see below
Step-by-step explanation:
The shape is a trapezoid
Base 1 (BH) is 10
Base 2 (QA) is 14
Height is 5
Area
Find distance between QB and HA
Q( -4,4) B (-2,9)
Perimeter
The first answer.
Point P is at (50,-40) the distance from Q to P is 80 units which you can find by subtracting the x of Q (-30) from the x of P (50).
50-(-30)=80
It then tells you point R is vertically above point Q so you know your x value for R will be the same as Q.
Add your distance from Q to P of 80 units to the y value of Q because you are traveling up.
-40+80=40
R will have a point of (-30,40) and a distance of 80 units
A complementary angle is an angle that adds up to 90 degree each and every time. So, therefore the correct formula to use is 90-63=27. Now, you have your answer and can check it twice if you'd like by the formula. Again your answer is 27.
Step-by-step explanation:
It is given that the angels of a triangle have a sum of 180°. The angles of a rectangle have a sum of 360°. The angels of a pentagon have a sum of 540.
<u>Let me define the each terms.</u>
1. We know that each angle in a triangle is 60°, So there is a three angle in a regular triangle.
2. We know that each angle in a rectangle, is 90°, So there is a four angle in a regular rectangle.
Similarly,
- There is 8 angle in a regular octagon and each angle measurement is 135°.
So, sum of the angles of an octagon = 135° × 8
Sum of the angles of an octagon = 1080°
Therefore, the required sum of the angles of an octagon is 1080°
