Answer:
-6i
Step-by-step explanation:
Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.
If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.
x + 8 = 0
x = -8
x - 1 = 0
x = 1
x^2 + 36 = 0
x^2 = -36 ... take the square root of both sides to get x alone
x = √-36 ... square root of an imaginary number produces the usual square root and an "i"
x = ±6i
Half = 0.5
x-the number
<span>Ten times the sum of half a number and 6 is 8:
10 · (0.5x + 6) = 8 |use distributive property: a(b + c) = ab + ac
5x + 60 = 8 |subtract 60 from both sides
5x = -52 |divide both sides by 5
<span>x = -10.4</span></span>
Answer:
100-36x^2y^2
Step-by-step explanation:
100-36x^2y^2 =
(10-6xy)(10+6xy)
Because x^2-y^2 = (x+y)(x-y)
Answer:
Yes!
Step-by-step explanation:
That’s because a square is a parallelogram with four congruent sides and four right angles.
Answer: We need to know the value of y >:3 Tricky Tricky
Step-by-step explanation:
