Answer: 
Step-by-step explanation:
Given : Sample size : n= 33
Critical value for significance level of
: 
Sample mean : 
Standard deviation : 
We assume that this is a normal distribution.
Margin of error : 
i.e. 
Hence, the margin of error is 
The margin of error is ±2%
<h3>What is Margin error?</h3>
A margin of error is a statistical measurement that accounts for the difference between actual and projected results in a random survey sample.
Let x be margin of error and y be the percentages of the population.
So,
y-x =33%
y +x = 37%
Solving above equations
2y= 70
y= 35%
and x= 2%
Hence, the margin of error is ±2%.
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Here are the CORRECT answers.
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The answer is the number 6
Answer:
A sample size of 1031 is required.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is of:

37% of freshmen do not visit their counselors regularly.
This means that 
98% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
You would like to be 98% confident that your estimate is within 3.5% of the true population proportion. How large of a sample size is required?
A sample size of n is required.
n is found when M = 0.035. So






Rounding up:
A sample size of 1031 is required.