Let a = Adult tickets, s = Student tickets; we are going to set up a system of equations.
8a + 4s = 880
a - s = 20
We are going to multiply the second equation by so that we can cancel out one of the variables and solve for the other. This gives you:
8a + 4s = 880
4a - 4s = 20
Notice the s-variables will cancel:
12a = 900
a = 75
Now we plug in the amount of adult tickets to solve for the student ones.
75 - s = 20
- s = - 55
Divide both sides by - 1
s = 55.
There were 55 student tickets sold and 75 adult tickets.
Answer:
y=x+3
(0,3)(1,4)
y=x+2
(0,2)(1,3)
Step-by-step explanation:
- For Y=X+3 it could be any point for Y as long as X is 3 less than Y.
- For Y=X+3 it could be any point for X and long as Y is 3 more than X.
- For Y=X+2 it could be any point for Y as long as X is 2 less than Y.
- For Y=X+2 it could be any point for X and long as Y is 2 more than X.
Answer:

Step-by-step explanation:
The correct question is
Large cheese pizzas cost $5 each and large one-topping pizzas cost $6 each.
Write an equation that represents the total cost, T, of c large cheese pizzas and d large one-topping pizzas.
Let
T -----> the total cost
c ----> the number of large cheese pizzas
d ---> the number of large one -topping pizzas
we know that
The total cost (T) is equal to the number of large cheese pizzas (c) multiplied by it cost ($5) plus the number of large one -topping pizzas (d) multiplied by it cost ($6)

<em>x</em> ^2 + <em>y</em> ^2 = 9 => <em>y</em> = <em>y(x)</em> = ± √(9 - <em>x</em> ^2)
Each cross section would be a square with side length equal to the vertical distance between the upper and lower semicircles defined by <em>y(x)</em>, which is
√(9 - <em>x</em> ^2) - (- √(9 - <em>x</em> ^2)) = 2 √(9 - <em>x</em> ^2)
The area of each square section is the square of this length,
(2 √(9 - <em>x</em> ^2)) = 4 (9 - <em>x</em> ^2) = 36 - 4<em>x</em> ^2
We get the whole solid for -3 ≤ <em>x</em> ≤ 3, so integrating gives a volume of
