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Nana76 [90]
3 years ago
10

Please help. show work.

Mathematics
1 answer:
ahrayia [7]3 years ago
8 0
17. To complete the square, add the square of half the x-coefficient.
  x² -8x +4² = 9 +4²
  (x -4)² = 25 = 5² . . rewrite as squares
  x -4 = ±5 . . . . . . . take the square root
  x = 4 ±5 . . . . . . . . add 4
The roots are x ∈ {-1, 9}.

18. The discriminant is b²-4ac. You have a=3, b=-5, c=4. So, the value of the discriminant is
  (-5)² -4(3)(4) = 25 -48 = -23
The discriminant is negative, so there are no real solutions.

19. You are asked to find the positive value of t such that h(t) = 0. This is equivalent to find solutions to
  -16t² +25t +3 = 0
The quadratic formula is
  t = (-b ±√(b² -4ac))/(2a)
where you have a=-16, b=25, c=3. The formula gives
  t = (-25 ±√(25² -4(-16)(3))/(2(-16))
  t = (-25 ±√817)/-32
  t ≈ 1.67447
The balloon will hit the ground after about 1.674 seconds.

20. The height at t=1 is found by substituting 1 for t in the equation for h(t).
  h(1) = -16×1² +25×1 +3
  h(1) = -16 +25 +3
  h(1) = 12
At t=1 second, the height of the balloon is 12 ft.

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Eric wants to get an output of 0. Can he do this with each machine? If so, how? If not, why not?
natita [175]

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  • <u>No, he can get an output of 0 with the second machine (function B) but he cannot get an output of 0 with the first machine (function A).</u>

Explanation

The way each machine works is given by the expression (function) inside it.

<u>1)  </u><em><u>Function A</u></em>

To get an output of 0 with the function y = x² + 3, you must solve the equation x² + 3 = 0.

Since x² is zero or positive for any real number, x² + 3 will never be less than 3 (the minimum value of x² + 3 is 3). So, it is not possible to get an output of 0 with the first machine.

<u>2) </u><em><u>Function B</u></em>

Solve y=\sqrt{x}-2=0

  • \sqrt{x}-2=0

  • \sqrt{x} =2

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So, he can get an output of 0 by using x = 4.

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3 years ago
How do I solve this? <br> Please help
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Top row outside box: 3c and 8
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Expanded: -3c - 8

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