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vfiekz [6]
3 years ago
10

Use the distributive property to simplify the expression below:

Mathematics
2 answers:
Lorico [155]3 years ago
8 0
4x + 2x + 2
= 6x + 2

So the answer is B
eduard3 years ago
5 0

Answer:

B)

Step-by-step explanation:

You would first multiply the variable and constant with the number next to the parenthesis. So you now have 4x+2x+2. Then you add up like terms to get a final answer of 6x+2.

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Robyn uses 1 cup of blueberries to make each loal
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1 cup of blueberries = 1 loaf, so 2 cups of blueberries = 2 loaves. The answer is 2
5 0
3 years ago
Which of the binomials below is a factor of this expression?<br> 16x2 + 40xy + 25y2
svet-max [94.6K]
(4x+5y)2 is the right answer
8 0
2 years ago
Read 2 more answers
Compare 9.36 and 9.359
Sati [7]

Try this option (this is not the only way!):

1. the rule: if 'number_1' - 'number_2' > 0, then number_1>number_2. If 'number_1'-'number_2'<0, then number_2>number_1.

2. according to the rule above: 9.36-9.359=0.001. 0.001>0, it means, 9.36>9.359.

6 0
3 years ago
An art club is going to a museum. Six adults are going. 18 more kids than adults are going. Adults tickets cost $24 each, which
dybincka [34]

so their are 6 adults and 24 kids because when you add 18+6  and get 24

then you multiply 6(24) because adult tickets are 24 and get 144

then you multiply 24(12) because student tickets are half as much as parents so they are 12 and you multiply by 24 kids and get 288

then you add 288 student tickets total price +144 adult ticket total price =432 total cost fro all tickets

8 0
3 years ago
4. (10 points) From the given triangle:
katrin2010 [14]

Answer:

sinθ =  y/r        sinθ = \frac{-6}{10} = \frac{-3}{5}

cosθ =  x/r       cosθ = \frac{8}{10} = \frac{4}{5}

tanθ =  y/x       tanθ =  \frac{-6}{8} =\frac{-3}{4}

cscθ =  r/y       cscθ = \frac{-5}{3}

secθ =  r/x       secθ =  \frac{5}{4}

cotθ = x/y       cotθ = \frac{4}{3}

explanation:

r = \sqrt{(8)^{2}+(-6)^{2}  }

r = 10

x = 8

y = -6

r = \sqrt{(4)^{2}+(3)^{2}  }

r = 5

x = 4

y = 3

7 0
3 years ago
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