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3 years ago

Does it seem plausible that employment has a normal distribution for each gender

Mathematics

1 answer:

Debora [2.8K]3 years ago

6 0

yes it is reasonable that employment has a normal distribution for each gender

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Solve for r. <br><br> √2/3r + 1 = 23

Keith_Richards [23]

Answer:

2nd option

Step-by-step explanation:

$\frac{\sqrt{2} }{3}$ r + 1 = 23 ( subtract 1 from both sides )

$\frac{\sqrt{2} }{3}$ r = 22 ( multiply both sides by 3 to clear the fraction )

$\sqrt{2}$ r = 66 ( divide both sides by $\sqrt{2}$ )

r = $\frac{66}{\sqrt{2} }$ × $\frac{\sqrt{2} }{\sqrt{2} }$ ( rationalising the denominator )

r = $\frac{66\sqrt{2} }{2}$ = 33 $\sqrt{2}$

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3 years ago

Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -6 and 162, respectively. Pl

kicyunya [14]

Hello,

$u_{0} =a\\
 u_{1} =a*r\\
 u_{2} =a*r^{2}=-6\\
 u_{3} =a*r^{3}\\
 u_{4} =a*r^{4}\\
 u_{5} =a*r^{5}=162\\
....\\
\boxed{ u_{n} =a*r^{n}} \\

\dfrac{ 162}{-6} = \dfrac{ u_{5} }{ u_{3}} = \dfrac{ a*r^{5}}{ a*r^{2}} =r^3= -27\\
==\ \textgreater \ r=-3\\

 u_{2} =a*r^{2}=-6=a*(-3)^2 \ ==\ \textgreater \ a=-\frac{6}{9} =-\frac{2}{3}\\


\boxed{ u_{n} =-\frac{2}{3}*(-3)^{n}=(-1)^{n+1}*2*3^{n-1}} \\

$

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3 years ago

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