- 10 51 76 13 69 79 18 20 2 1

Simplify without using the calculator or the sin tables.

katovenus [111]

Answer:

1/8

Step-by-step explanation:

sin²(π/8) − cos⁴(3π/8)

Use power reduction formulas:

1/2 (1 − cos(2×π/8)) − 1/8 (3 + 4 cos(2×3π/8) + cos(4×3π/8))

Simplify:

1/2 (1 − cos(π/4)) − 1/8 (3 + 4 cos(3π/4) + cos(3π/2))

1/2 (1 − √2/2) − 1/8 (3 + 4 (-√2/2) + 0)

1/2 − √2/4 − 1/8 (3 − 2√2)

1/2 − √2/4 − 3/8 +√2/4

1/2 − 3/8

1/8

7 0

3 years ago

For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel

adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives q in terms of p, the elasticity of demand is

$E=|\frac{p}{q}\cdot \frac{dq}{dp} |$

If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
If E = 1, we say demand is unitary.

We have the following demand equation $D(p)=-\frac{3}{4}p+29$ ; p = 9

Applying the above definition of elasticity of demand we get:

$E(p)=\frac{p}{q}\cdot \frac{dq}{dp}$

where

p = 9
q = $-\frac{3}{4}p+29$
$\frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)$

$\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}$

Substituting the values

$E(9)=\frac{9}{-\frac{3}{4}(9)+29}\cdot -\frac{3}{4}\\\\E(9)=\frac{36}{89}\cdot -\frac{3}{4}\\\\E(9)=-\frac{27}{89}\approx -0.30337$

$|E(9)|=|\frac{27}{89}| < 1$

Demand is inelastic at p = 9 and therefore revenue will increase with an increase in price.

6 0

3 years ago

What is the value of the x-coordinate of point W? Enter your answer as a decimal to the nearest 0.5.

levacccp [35]

I attached a screenshot with the complete question.

Answer:
x-coordinate of point w is nearly -3.5

Explanation:
To get the x-coordinate of a certain point, we would need to read the value of this point on the horizontal axis (the x-axis).
Taking a look at point w, we would find that it is in the second quadrant. This means that it has a negative x-value.
Now, reading the x-value on the horizontal axis, we can see that it is nearly midway between points -3 and -4.
This means that point w is approximately -3.5

Hope this helps :)