An absolute value inequality for "all numbers less than 7 and greater than -7" is given by |x| < 7.
<h3>How to write an absolute value inequality?</h3>
Based on the information provided, we can logically deduce that the statement describes an intersection of set because the word "and" was used.
This ultimately implies that, we would use the less than (<) symbol to write an absolute value inequality for the given statement:
|x| < 7
Therefore, this can be translated as follows:
-7 < x < 7 or x < 7 and x > -7.
Read more on number line here: brainly.com/question/24644930
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Answer:
1/4
Step-by-step explanation:
we can take two points on the line: (0,2) and (4,3)
to find slope:(2-3)/(0-4)
1/4
Answer:
D, The last one
Step-by-step explanation:
Hope this Helps!
Answer:
Σ(-1)^kx^k for k = 0 to n
Step-by-step explanation:
The nth Maclaurin polynomials for f to be
Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......
The given function is.
f(x) = 1/(1+x)
Differentiate four times with respect to x
f(x) = 1/(1+x)
f'(x) = -1/(1+x)²
f''(x) = 2/(1+x)³
f'''(x) = -6/(1+x)⁴
f''''(x) = 24/(1+x)^5
To calculate with a coefficient of 1
f(0) = 1
f'(0) = -1
f''(0) = 2
f'''(0) = -6
f''''(0) = 24
Findinf Pn(x) for n = 0 to 4.
Po(x) = 1
P1(x) = 1 - x
P2(x) = 1 - x + x²
P3(x) = 1 - x+ x² - x³
P4(x) = 1 - x+ x² - x³+ x⁴
Hence, the nth Maclaurin polynomials is
1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n
= Σ(-1)^kx^k for k = 0 to n
Answer:
Bolt A will fit Nut A and Nut B
Step-by-step explanation:
We have the following statements:
Nut C fits on Bolt C.
Nut B fits on Bolt B.
Nut A fits on Bolt A.
Bolt C is larger than Bolt B.
Bolt A and Bolt B are exactly the same.
Then we can say that Bolt A will fit Nut A and Nut B...
