Answer:
A - 4/13ths is a larger number
B- 3/10ths is a ratoinal mumner
Answer:
- The function f(x) = 9,000(0.95)^x represents the situation.
- After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
- The range values, in the context of the situation, are limited to whole number
Step-by-step explanation:
The "growth" rate is -5%, so the growth factor, the base in the exponential equation, is 1.00-5% =0.95.
Using x=2, we find the population in 2 years is expected to be about ...
f(2) = 9000·0.95^2 ≈ 8123 . . . . about 8120
Using x=4, we find the population in 4 years is expected to be about ...
f(4) = 9000·0.95^4 ≈ 7331 . . . . about 7330
Since population is whole numbers of bees, the range of the function is limited to whole numbers.
The domain of the function is numbers of years. Years can be divided into fractions as small as you want, so the domain is not limited to whole numbers.
The choices listed above are applicable to the situation described.
Answer:
0 = 6
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
3(m−1)=5m+3−2m
(3)(m)+(3)(−1)=5m+3+−2m (Distribute)
3m+−3=5m+3+−2m
3m−3=(5m+−2m)+(3) (Combine Like Terms)
3m−3=3m+3
3m−3=3m+3
Step 2: Subtract 3m from both sides.
3m−3−3m=3m+3−3m
−3=3
Step 3: Add 3 to both sides.
−3+3=3+3
0=6
Answer:
-2 ≤ n < 8
Step-by-step explanation:
_________________
Answer:
μ ≈ 2.33
σ ≈ 1.25
Step-by-step explanation:
Each person has equal probability of ⅓.
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The mean is the expected value:
μ = E(X) = ∑ X P(X)
μ = (1) (⅓) + (2) (⅓) + (4) (⅓)
μ = ⁷/₃
The standard deviation is:
σ² = ∑ (X−μ)² P(X)
σ² = (1 − ⁷/₃)² (⅓) + (2 − ⁷/₃)² (⅓) + (4 − ⁷/₃)² (⅓)
σ² = ¹⁴/₉
σ ≈ 1.25
