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finlep [7]
3 years ago
11

What is 1/2 of 2 3/4?

Mathematics
1 answer:
luda_lava [24]3 years ago
5 0

Answer:

1 3/8

Step-by-step explanation:

First, change the mixed fraction to improper fraction.

2 3/4 = 8/4 + 3/4 = 11/4

1/2 of 11/4 = (11/4)(1/2) = 11/8

11/4 - 11/8 = 22/8 - 11/8 = 11/8

11/8, or 1 3/8 is your answer.

~

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write the x and y coordinate (in the second and third column, respectively) of dilation of quadrilateral ABCD with vertices A(1,
gayaneshka [121]

Answer:

The coordinates of the dillated vertices are A'(x,y) = (2,2), B'(x,y) = (4,4), C'(x,y) = (8,2) and D'(x,y) = (4,-2).

Step-by-step explanation:

From Linear Algebra, we define dilation by the following equation:

P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)] (1)

Where:

O(x,y) - Center of dilation, dimensionless.

P(x,y) - Original point, dimensionless.

k - Scale factor, dimensionless.

P'(x,y) - Dilated point, dimensionless.

If we know that O(x,y) = (0, 0), k = 2, A(x,y) = (1,1), B(x,y) = (2,2), C(x,y) = (4,1) and D(x,y) = (2,-1), then the dilated points are, respectively:

Point A

A'(x,y) = O(x,y) + k\cdot [A(x,y)-O(x,y)] (2)

A'(x,y) = (0,0) + 2\cdot [(1,1)-(0,0)]

A'(x,y) = (2,2)

Point B

B'(x,y) = O(x,y) + k\cdot [B(x,y)-O(x,y)] (3)

B'(x,y) = (0,0) + 2\cdot [(2,2)-(0,0)]

B'(x,y) = (4,4)

Point C

C'(x,y) = O(x,y) + k\cdot [C(x,y)-O(x,y)]

C'(x,y) = (0,0) + 2\cdot [(4,1)-(0,0)]

C'(x,y) = (8,2)

Point D

D'(x,y) = O(x,y) + k\cdot [D(x,y)-O(x,y)]

D'(x,y) = (0,0) + 2\cdot [(2,-1)-(0,0)]

D'(x,y) = (4,-2)

The coordinates of the dillated vertices are A'(x,y) = (2,2), B'(x,y) = (4,4), C'(x,y) = (8,2) and D'(x,y) = (4,-2).

4 0
2 years ago
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Answer:

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Answer:

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