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bekas [8.4K]
2 years ago
11

Bob was thinking of two numbers. He said the larger of his numbers was 8 more than the smaller number. He chose to represent the

smaller number with an x. Which of the following is an expression that can be used to represent the larger number in terms of x?
Mathematics
1 answer:
harkovskaia [24]2 years ago
4 0

Answer:

x+8

Step-by-step explanation:

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i have 6 digits. One of my 3s is worth 300.000. The other is worth 1/10 as much. My 6 is worth 600.The rest of my digits are zer
motikmotik
The way you wrote the problem makes the answer 330,600. I think your decimals were meant to be commas. If I am wrong, please forgive me.
3 0
3 years ago
John accepted a reduction of 15% on his salary when his company was not doing well. Now his company's financial position has imp
o-na [289]
To reverse a percentage decrease you divide it by the decrease (+ 100%)
For example we will pick the number, 100, which is decreased by 15% to 85.

To make 85 back to 100 we divide it by the decrease (1-0.15):
85 / 0.85 = 100

To find out how much 85 increased to get back to 100, we do:
15 / 85 = 0.1765 = %17.65

15 is the reduction/difference, and 85 is the with reduction total.

Because percentages stay the same, this is applicable to any numbers, from this, we know that whenever something is reduced by 15% - when restored to it's original is increased by %17.65

The answer is %17.65


6 0
3 years ago
A park ranger has 32 feet of fencing to fence four sides of a rectangular recycling site. What is the greatest area of recycling
Crazy boy [7]
Go go power rangers
3 0
3 years ago
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One urn contains one blue ball (labeled b1) and three red balls (labeled r1, r2, and r3). a second urn contains two red balls (r
Flura [38]

Answer:

12 possibilities

Step-by-step explanation:

In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.

The same thing occurs in the second urn, as all balls have different labels.

The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).

For the first urn, we have a combination of 4 choose 2:

C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities

For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.

In total we have 6 + 6 = 12 possibilities.

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3 years ago
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Divide . Write the quotient as one power. The variable is not equal to zero.
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I need the equation to be able to help
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2 years ago
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