Answer:
0.02.90 and 2.90
Step-by-step explanation:
2% of 90 equal to both 0.02.90 because are worth same.
Answer:
No extraneous solution
Step-by-step explanation:
We have the logarithmic equation given by,
![\log_{2}[\log_{2}(\sqrt{4x})]=1](https://tex.z-dn.net/?f=%5Clog_%7B2%7D%5B%5Clog_%7B2%7D%28%5Csqrt%7B4x%7D%29%5D%3D1)
i.e. 
i.e. 
i.e. 
i.e. 
i.e. 
i.e. 
So, the solution of the given equation is x=4.
Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is
.
Therefore, the domain of the given function is x > 0.
We know that the extraneous solution is the solution which does not belong to the domain.
But as x=4 belongs to the domain x > 0.
Thus, x = 4 is not an extraneous solution.
Hence, this equation does not have any extraneous solution.
13. five plus <em>y</em> equal to negative two. y = -7
14. eight plus <em>h</em> equal to twelve. h = 4
15. negative thirteen plus four equal <em>n</em>. n = -9
Step-by-step explanation:

Answer: No, the friend is correct. In any function, each input value can only lead to one output value. When you input 3 for the x-values, you would get two output values because 3 is included in both equations. To fix this, you need to have the 3 not included in one of the equations.
For example, you could say
or
because the input value of 3 would not be included twice.
If you look at the attached screenshot, you will see that if you keep your friend's function, inputting 3 will result in two outputs of 4 and -3, so therefore,
cannot represent a piecewise function.