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Allushta [10]
2 years ago
10

The accompanying specific gravity values describe various wood types used in construction. 0.34 0.35 0.36 0.36 0.37 0.38 0.40 0.

40 0.40 0.41 0.41 0.42 0.42 0.42 0.42 0.42 0.43 0.44 0.45 0.46 0.46 0.47 0.48 0.48 0.49 0.51 0.54 0.54 0.55 0.58 0.61 0.66 0.66 0.67 0.68 0.76
Construct a stem-and-leaf display using repeated stems.
Comment on any interesting features of the display.
a. The display is symmetric.
b. The display is not symmetric and appears to be positively skewed.
c. There is a small amount of variation in the data.
d. The stem-and-leaf display shows that 0.45 is a good representative value for the data.
e. There is a reasonably large amount of variation in the data.
f. The data value 0.33 is a possible outlier.
g. The stem-and-leaf display shows that 0.55 is a good representative value for the data.
h. The data value 0.76 is a possible outlier.
Mathematics
1 answer:
Delicious77 [7]2 years ago
4 0

Answer:

h. The data value 0.76 is a possible outlier.

b. The display is not symmetric and appears to be positively skewed.

d. The stem-and-leaf display shows that 0.45 is a good representative value for the data.

Step-by-step explanation:

STEM | LEAF

3 ___ | 4

3 ___ | 5, 6, 6, 7, 8

4 ___ | 0, 0, 0, 1, 1, 2, 2, 2, 2, 2, 3, 4

4 ___ | 5, 6, 6, 7, 8, 8, 9

5 ___ | 1, 4, 4

5 ___ | 5, 8

6 ___ | 1

6 ___ | 6, 6, 7, 8

7 ___

7 ___ | 6

The data point which seems a bit further out from the rest of the values : 0.76

0.45 is the median value and gives a reasonable representative value of the data.

Majority of the data accumulates on the left and this makes distribution positively skewed.

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3 0
3 years ago
The proportions of blood phenotypes, A, B, AB, and O, in the population of all Caucasians in the United States are approximately
Vanyuwa [196]

Answer:

a. S = {A,B,AB,O}

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Step-by-step explanation:

a List the sample space for this experiment.

All possible blood types(A, B, AB or O). So

S = {A,B,AB,O}

b Make use of the information given above to assign probabilities to each of the simple events.

The proportions of blood phenotypes, A, B, AB, and O, in the population of all Caucasians in the United States are approximately .41, .10, .04, and .45, respectively.

So

P(A) = 0.41, P(B) = 0.1, P(AB) = 0.04, P(O) = 0.45

c What is the probability that the person chosen at random has either type A or type AB blood

P(A) + P(AB) = 0.41 + 0.04 = 0.45

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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