All categories

3 years ago

How are unlike fractions identified

2 answers:

7 0

When the terms do not have the same number or the other vaue, it must be given in your maths book,chapter related to fractions

dem82 [27]3 years ago

3 0

We can identify unlike fractions by looking the denominator.In unlike fractions the denominators will be different.E.g..1/2,5/3,6/5 are unlike fractions while 1/2,5/2,6/2 are like fractions

You might be interested in

PLEASE HELP ASAP!!!!!!!!!!

alexgriva [62]

I think it is 715 mph but I may have done my math wrong....

5 0

3 years ago

Kristen is 64 inches tall, and she stands 12 feet away from a streetlight. If she casts an 82-inch-long shadow, how tall is the

o-na [289]

Answer:

176.39 inches or

14.70 feet

Step-by-step explanation:

Consider the right triangle made by Kristen, ground and shadow.

This triangle has one leg as 64 inches.

Next consider the right triangle formed by street light, ground upto shadow tip.

The two triangles have common angle of elevation and also another angle as 90 degrees.

Hence the two triangles would be similar

Also if A is the angle made by hypotenuse of both triangles with the ground we have

$tanx=\frac{64}{82}$

This value also equals by bigger triangle as

$tanx=\frac{h}{82+12(12)}=\frac{h}{226}$

From these two we get

h = height of street light = $\frac{226(64)}{82} =176.39$

6 0

2 years ago

What are the holes, VA, domain, HA, and Range of n+8/6n? Please help!!

-BARSIC- [3]

Answer:

We show that f(x) n+8/6n = 6 x n = 0

which flips the n+8/1 = 0+8/0-6= x = 3 this is the range.

For the HA we would work left to right.

x goes to positive or negative infinity and is determined by the highest degree terms of the polynomials in the numerator and the denominator. This particular function has polynomials of degree 0 in both the numerator and the denominator

If say n+8 was n+2 then we would use the 2/-2+3 and get 1 and show the hole as the source;

hole : -2+1 as non equal sign. but not in the case of n+8/6n

-2+1 represents 1/3 symmetry.

We see for n+8/6n with interpreted back into the zero format minus

-0+8/-0-6 we see there is symmetry and can work on the left side of graph and flip over. Where 0 = n+8 and 1=nx6

Step-by-step explanation:

There would be no way of doing the others unless the exponents had been squared ^2

If they were squared then the domain will be (-infinity -3) parenthesis

union of( -3 -2) union of +2 to negative infinity.

There is not a vertical asymptote as the numerator divides into dominator at point 8 as a decimal.

The holes are then closed.

7 0

2 years ago

Look at this graph: y : Is this relation a function? yes no Submit

iren [92.7K]

Answer:

Yes

Step-by-step explanation:

3 0

2 years ago

A scientist has two solutions, which she has labeled solution A and solution B. Each contains salt. She knows that solution A is

Irina-Kira [14]

First off... let's use the decimal format for the percentages, so 85% is 85/100 or 0.85 and 45% is 45/100 or 0.45 and so on

let's say the quantities of each are "a" and "b" respectively

how much salt concentration in A? well, 0.45, so for a quantity "a", that'd be 0.45a

how much satl concentration in B? well 0.85, so for a quantity "b", that'd be 0.85b

now, she wants a mixture of 160ounces with 70% concentration, or 0.7

so the mixture will have a concentration amount of salt of 160 * 0.7

$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{sol'n A}&a&0.45&0.45a\\
\textit{sol'n B}&b&0.85&0.85b\\
-----&-----&-------&-------\\
mixture&160&0.7&112.0
\end{array}
\\\\\\

\begin{cases}
a+b=160\implies \boxed{b}=160-a\\
0.45a+0.85b=112\\
----------\\
0.45a+0.85\left( \boxed{160-a} \right)=112
\end{cases}$

solve for "a", to see how much of the 45% solution will be needed.

what about "b"? well, b = 160 - a

8 0

3 years ago

Read 2 more answers