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Sauron [17]
3 years ago
5

Marco has a bag of 50 colored marbles.there are 12 blue marbles,18 black marbles,and 20 red marbles.what is the ratio of the num

bers of black marbles to the number of blue marbles
Mathematics
1 answer:
iren2701 [21]3 years ago
8 0

The answer is 2:3 because it is 12:18 simplified.

You might be interested in
Simplify (x − 4)(3x2 − 6x + 2). 3x3 + 6x2 − 22x + 8 3x3 − 18x2 + 26x − 8 3x3 − 18x2 − 22x − 8 3x3 + 6x2 + 22x + 8
kogti [31]

Answer:

3x^3-18x^2+26x-8

Step-by-step explanation:

(x-4)(3x^2-6x+2)

3x^3-6x^2+2x-12x^2+24x-8

3x^3-18x^2+26x-8

5 0
3 years ago
Confusing I tried <br><br> 4x-7+31=4x+2<br><br> But it won’t work <br><br><br> Can someone explain??
Len [333]

Answer:

0=-22

4x−7+31=4x+2

Step 1: Simplify both sides of the equation.

4x−7+31=4x+2

4x+−7+31=4x+2

(4x)+(−7+31)=4x+2(Combine Like Terms)

4x+24=4x+2

4x+24=4x+2

Step 2: Subtract 4x from both sides.

4x+24−4x=4x+2−4x

24=2

Step 3: Subtract 24 from both sides.

24−24=2−24

0=−22.

if it's help can you give me brianliest ??

8 0
3 years ago
Which equation should be used to graph y=sec^-1(x) on a calculator ?
erastova [34]
Arcsecant or arcsec or sec⁻¹ is an inverse trigonometric function. And many calculators don't have a key for them because they can be calculated with basic trigonometric functions like so:

sec⁻¹(x)=cos⁻¹(1/x). 

So the correct answer is the fourth one: y=cos⁻¹(1/x).
4 0
3 years ago
A worker is to construct an open rectangular box with a square base and a volume of 196196 ft cubedft3. If material for the bott
Archy [21]

Answer:

Therefore the dimensions of the box is 7 ft by 7 ft by 4 ft.

Therefore the minimum cost to manufacture the box is $12936.

Step-by-step explanation:

Given the volume of the open box is 196 cube ft.

Let the one side of the base of the box be x.

Since the base of the box is square in shape.

The other side of the base is also x.

The area of the base of the box = x² square ft

Let the height of the box be h.

The volume of the box is = Area of the base× height

                                          =(x²×h) cube ft.

                                           =x²h cube ft.

According to the problem,

x²h=196

\Rightarrow h=\frac{196}{x^2}

The material cost for the bottom is $88 per square ft and the material cost for the sides $77  per square ft.

The material cost for the bottom of the box = $(88×x²)

                                                                         =$88x²

The area sides = 2(length+width)height

                       =2(x+x)h

                      =4xh square ft.

The material cost for the sides of the box =$(77×4xh)

                                                                    =$308 xh

Total cost to make the box is =$(88x²+308 xh)

∴C=88x²+308 xh    [ C is in dollar]

Now putting h=\frac{196}{x^2}

C=88x^2+308x\times \frac{196}{x^2}

\Rightarrow C=88x^2+ \frac{60368}{x}

Differentiating with respect to x

C'=176x- \frac{60368}{x^2}

Again differentiating with respect to x

C''=176+ \frac{120736}{x^3}

Now to find the minimum cost, we set C'=0

\therefore 176x- \frac{60368}{x^2}=0

\Rightarrow 176x= \frac{60368}{x^2}

\Rightarrow x^3= \frac{60368}{176}

\Rightarrow x^3=343

\Rightarrow x=7

Now, C''|_{x=7}=176+ \frac{120736}{7^3}>0

Therefore at x=7, the manufacturing cost will be minimum.

The height of the box is h=\frac{196}{7^2} = 4ft

Therefore the dimensions of the box is 7 ft by 7 ft by 4 ft.

The manufacturing cost is C=88.7^2+ \frac{60368}{7}   [ putting x=7]

                                             =$12936

Therefore the minimum cost to manufacture the box is $12936.

4 0
3 years ago
How many 3-letter sequences can be formed if the second letter must be a vowel (A, E, I, O, or U), and the third letter must be
erica [24]

Answer:

120 ways

Step-by-step explanation:

Given that, 3-letter sequences should be formed, where the second letter must be a vowel (A, E, I, O, U) and the third letter must differ from the first letter.

There are 26 alphabets in English,

so, firstly let us fix the second letter to be one of the vowels

now we are left with 25 alphabets and now let us fix the third letter to be an alphabet from the remaining 25 alphabets.

now, we are left with 24 alphabets and the first letter can be any of these 24 alphabets.

so, there are 24 ways to fill the sequence.

The same thing can be done with the other 4 vowels.

so, total number of ways =   5 × 24 = 120 ways.

 

8 0
3 years ago
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