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4 years ago

How do you convert from scientific notation to standard notation?

Mathematics

1 answer:

lina2011 [118]4 years ago

7 0

Answer:

here is an example of scientific to standard...

2.36*10^6

you would write out 2.36 and move 6 times to the right (because the exponent on 10 is positive)

so like this 2.36= 2360000

Step-by-step explanation:

You might be interested in

The distance between -18 and 15 is equal to _____.

Komok [63]

Answer:

15 -(-18)

Step-by-step explanation:

a double negative is basically a + sign. The distance between -18 & 15 is 33, so 15- (-18) or 15 + 18 is 33 is equivalent

4 0

4 years ago

Read 2 more answers

(2n – 3)(5n+6)<br> How do I solve this ?

nalin [4]

Answer:

Step-by-step explanation:

(2n - 3)(5n + 6) = 2n*(5n + 6) -3*(5n +6)

=2n*5n + 2n*6 -3*5n + (-3)*6

=10n² + 12n - 15n - 18

= 10n² -3n - 18

5 0

3 years ago

Read 2 more answers

Given the following linear functio, determine the slope of a line parallel to f(x)

andrew11 [14]

Answer:

Option C is correct.

C. 4/3

Step-by-step explanation:

Given:

The given linear function of a line.

F(x)=4/3x+2

We need to determine the slope of a line parallel to F(x)=4/3x+2

Solution:

First we compare the given function of the line with standard form of a line. $y = mx + c$

Where m = slope of the line.

And c = y-intercept

So, the slope of the line $m=\frac{4}{3}$ and y-intercept $c=2$

We know that the slope of the parallel lines are same.

Therefore, the slope of a the parallel line $m=\frac{4}{3}$ .

8 0

3 years ago

Given f(x), find g(x) and h(x) such that f(x)=g(h(x)) and neither g(x) nor h(x) is solely x. f(x)=−3x+4⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√3+5

iVinArrow [24]

Answer:

$h(x)=-2x+4$

$g(x)=\sqrt[3]{x}-5$

Step-by-step explanation:

Consider the given function is

$f(x)=\sqrt[3]{-2x+4}-5$

It is given that $f(x)=g(h(x))$ and neither g(x) nor h(x) is solely x.

$f(x)=\sqrt[3]{(-2x+4)}-5$

Let $h(x)=-2x+4$ , then we get

$f(x)=g(h(x))=\sqrt[3]{h(x)}-5$

Substitute h(x)=x in the above function.

$g(x)=\sqrt[3]{x}-5$

Therefore, the required functions are $h(x)=-2x+4$ and $g(x)=\sqrt[3]{x}-5$ .

Check the solutions.

$g(h(x))=g(-2x+4)$ $[\because h(x)=-2x+4]$

$g(h(x))=\sqrt[3]{-2x+4}-5$ $[\because g(x)=\sqrt[3]{x}-5]$

$g(h(x))=f(x)$

Therefore, our solution is correct.

7 0

4 years ago

Factor the expression using GCF <br> 15w + 65

labwork [276]

That would be 5(3w + 13)

The GCF is 5

5 0

4 years ago