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liubo4ka [24]
3 years ago
5

Graph a line that contains the point (6,-5) and has a slope of - 2/3

Mathematics
1 answer:
just olya [345]3 years ago
7 0

Answer:

The equation of line with slope \dfrac{-2}{3}  and passing through points ( 6 , - 5 ) is

y = ( \dfrac{-2}{3} )x - 1   and graph shown

Step-by-step explanation:

Given as :

The points on the line is (6 , - 5)

The slope is m =  \dfrac{-2}{3}

Now, The equation of line with slope \dfrac{-2}{3} and passing through points ( 6 , - 5) is

y = m x + c is the standard line equation

Now , satisfying the points

So, - 5 = ( \dfrac{-2}{3} ) × 6 + c

or, - 5 = \frac{-2\times 6}{3}  + c

Or, - 5 = - 4 +  c

Or, c = - 5 + 4

∴  c = - 1

So, The equation of line with slope \dfrac{-2}{3}  and passing through points ( 6 , - 5 )

y = ( \dfrac{-2}{3} ) × x - 1

Now, Plotting the line on graph

For x = 0 , y = 0 - 1 = -1

For , y = 0 , x = \dfrac{-3}{2}

So, points as ( 0 , - 1) and ( \dfrac{-3}{2} , 0)

Hence , The equation of line with slope \dfrac{-2}{3}  and passing through points ( 6 , - 5 ) is y = ( \dfrac{-2}{3} )x - 1    and graph shown Answer

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Step-by-step explanation:

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3 years ago
Emma had $2.40 to spend on seven pencils. After buying them she had $1.00. How much did each pencil cost?
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Aleks04 [339]

Answer:

\displaystyle d \approx 7.62

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  4. Multiplication
  5. Division
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<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

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<u>Step 2: Find distance </u><em><u>d</u></em>

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  1. Substitute in points [DF]:                    \displaystyle d = \sqrt{(-2-1)^2+(-3-4)^2}
  2. (Parenthesis) Subtract:                       \displaystyle d = \sqrt{(-3)^2+(-7)^2}
  3. [√Radical] Exponents:                        \displaystyle d = \sqrt{9+49}
  4. [√Radical] Add:                                   \displaystyle d = \sqrt{58}
  5. [√Radical] Evaluate:                           d = 7.61577
  6. Round:                                                 \displaystyle d \approx 7.62
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I need help on this answer and don't know. Do you know how to do it?????
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