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mixer [17]
3 years ago
5

I NEED HELP ASAP PLEASE!!!

Mathematics
1 answer:
Colt1911 [192]3 years ago
3 0

Answer:

h= 2/3d

Step-by-step explanation:

slope is the change of y value on the change of x value

4/6 = 2/3

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aev [14]

Answer:

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7 0
3 years ago
Solve this problem.
nikklg [1K]

Answer:

24

Step-by-step explanation

40 times .60

8 0
2 years ago
From the following numbers, select all that are rational.<br>A.6/7<br>B. 0.62<br>C. 0.6<br>D. 0.6π​
uysha [10]

Answer:

All those canbe expressed in the form of p/q, where q≠0 are rational

clearly A is rational

now 0.62 =62/100=31/50----its also rational

and 0.6 =6/10=3/5--- it's also rational

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✌️:)

8 0
3 years ago
1, 3/2 , 9,4 ...<br> Find the 9th term HELP ASAP
yarga [219]
This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by
2
3
2
3
gives the next term. In other words,
a
n
=
a
1
⋅
r
n
−
1
a
n
=
a
1
⋅
r
n
-
1
.
Geometric Sequence:
r
=
2
3
r
=
2
3
This is the form of a geometric sequence.
a
n
=
a
1
r
n
−
1
a
n
=
a
1
r
n
-
1
Substitute in the values of
a
1
=
1
2
a
1
=
1
2
and
r
=
2
3
r
=
2
3
.
a
n
=
(
1
2
)
⋅
(
2
3
)
n
−
1
a
n
=
(
1
2
)
⋅
(
2
3
)
n
-
1
Apply the product rule to
2
3
2
3
.
a
n
=
1
2
⋅
2
n
−
1
3
n
−
1
a
n
=
1
2
⋅
2
n
-
1
3
n
-
1
Multiply
1
2
1
2
and
2
n
−
1
3
n
−
1
2
n
-
1
3
n
-
1
.
a
n
=
2
n
−
1
2
⋅
3
n
−
1
a
n
=
2
n
-
1
2
⋅
3
n
-
1
Cancel the common factor of
2
n
−
1
2
n
-
1
and
2
2
.
Tap for more steps...
a
n
=
2
n
−
2
3
n
−
1
a
n
=
2
n
-
2
3
n
-
1
Substitute in the value of
n
n
to find the
n
n
th term.
a
5
=
2
(
5
)
−
2
3
(
5
)
−
1
a
5
=
2
(
5
)
-
2
3
(
5
)
-
1
Simplify the numerator.
Tap for more steps...
a
5
=
8
3
(
5
)
−
1
a
5
=
8
3
(
5
)
-
1
Simplify the denominator.
Tap for more steps...
a
5
=
8
81
a
5
=
8
81
4 0
2 years ago
Add −1.25+2.5<br><br> Plot the first addend and the sum on the number.<br> Please tell the explain
Assoli18 [71]
If signs are different you subtract. So 2.5- -1.25 equals 1.25 and keep the sign of the biggest number
7 0
2 years ago
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