Answer:
1000
Step-by-step explanation:
Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
Answer: 87.5
Step-by-step explanation:
Triangle area = base * height / 2
25 * 7 = 175
175/ 2 = 87.5
Answer:
Step-by-step explanation:
f(x) = x + 2.....change f(x) to y
y = x + 2....now switch x and y and solve for y
x = y + 2
x - 2 = y....change y to f-1(x)...represents an inverse
f-1(x) = x - 2 <== ur inverse
Find all the common factors ... answer is 2u^3v^2