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Tema [17]
3 years ago
15

Which equation is written in slope-intercept form? y=3x-2 x=1/2y+8 2x+5y=12 3y=8x-5

Mathematics
2 answers:
kumpel [21]3 years ago
6 0

Slope-intercept form is y=mx+b

So y=3x-2 is in slope-intercept

Triss [41]3 years ago
5 0

Answer:

y=3x-2

Step-by-step explanation:

Because the equation for slope intercept form is y=mx+b!

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I need to know what to do
Vadim26 [7]

Answer:

210000*1.125^t=f(t)


7 0
2 years ago
For which of the following displays of data is it not possible to find the mean?
myrzilka [38]

Answer: Histogram

You can eliminate the stem and leaf plot, since it tells you the amount of values.

You can eliminate the dot plot, since it also shows you the number of values.

You can eliminate the frequency table, since it calculates the frequency of a number.

Thus, the answer is the histogram.

8 0
2 years ago
Read 2 more answers
1/2 of the people in the clinic are men, 1/3 are elderly, how many people are not elderly or men?
Nostrana [21]

1/6 of the people are not elderly or men

<h3>How to determine the proportion?</h3>

The given parameters are:

Men = 1/2

Elderly = 1/3

The number of people that are not elderly or men are:

People = 1 - Men - Elderly

So, we have:

People = 1 - 1/2 - 1/3

Evaluate

People = 1/6

Hence, 1/6 of the people are not elderly or men

Read more about proportion at:

brainly.com/question/1781657

#SPJ1

7 0
2 years ago
Please help me complete this !! 12points
Svet_ta [14]

Answer:

1.

x1=1

x2=3

y1=5

y2=1

midpoint= (x1+x2/2, y1+y2/2)=(1+3/2,5+1/2)=(2,3)

2.

x1=2

x2=4

y1=4

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(2+4/2,4+6/2)=(3,5)

3.

x1= -2

x2=4

y1=4

y2= -6

midpoint= (x1+x2/2, y1+y2/2)=(-2+4/2,4-6/2)=(1,-1)

4.

x1=0

x2=0

y1=3

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(0/2,3+5/2)=(0,4)

5.

x1= -2

x2=2

y1= -6

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(-2+2/2,-6+6/2)=(0,0)

6.

x1=1

x2=4

y1=4

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(1+4/2,4+5/2)=(5/2,9/2)

7.

x1=-3

x2=-4

y1=5

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(-3-4/2,5+5/2)=(-7/2,5)

8.

x1=5

x2= -4

y1=2

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(5-4/2,2+6/2)=(1/2,4)

3 0
2 years ago
PLEASE HELP!! if f(x)= 2x^2-11, find f(4)
Lemur [1.5K]

Answer: f(4) = 21

Step-by-step explanation:

2(4)^2-11

4^2 = 16

2(16)-11

Multiply 2 and 16

32 - 11

Subtract

21

4 0
2 years ago
Read 2 more answers
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