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Roman55 [17]
3 years ago
10

When do u evaluate exponents in the order of operations?? Pls help I got 9 minutes to do this

Mathematics
2 answers:
wlad13 [49]3 years ago
6 0

Answer: Great more than happy to help!

Exponents come 2nd in line for PEMDAS (order of operations).

Once you finish the parenthesis, you move on to the exponents.

Step-by-step explanation:

Strike441 [17]3 years ago
5 0

Answer:

Step-by-step explanation:

Using the PEMDAS

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

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igomit [66]

Answer:

\large\boxed{x=-\dfrac{7-\sqrt{97}}{4}\ \vee\ x=-\dfrac{7+\sqrt{97}}{4}}

Step-by-step explanation:

ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta0,\ \text{then an equation has two solutions:}\ x=\dfrac{-b\pm\sqrt\Delta}{2a}\\\\\text{We have:}\\\\-2x^2-7x+10=4\qquad\text{subtract 4 from both sides}\\\\-2x^2-7x+6=0

a=-2,\ b=-7,\ c=6\\\\\Delta=(-7)^2-4(-2)(6)=49+48=97>0\\\\\sqrt\Delta=\sqrt{97}\\\\x=\dfrac{-(-7)\pm\sqrt{97}}{2(-2)}=\dfrac{7\pm\sqrt{97}}{-4}=-\dfrac{7\pm\sqrt{97}}{4}

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Amy deposits $360 in an account that pays 1/2% simple annual interest. How much interest will she earn in 6 years?
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Let sin A= -3/5 with 270°&lt; A&lt; 360°. Find the following.<br> sin A/2
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Answer:

1/sqrt10

Step-by-step explanation:

1) Find out cosA using formula (cosA)^2+(sinA)^2=1

The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5

So cosA=-4/5 or cosA=4/5.

Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.

2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.

(sinA/2)^2= 0.1

sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10

But 270°< A< 360°, then 270/2°<A/2<360/2°

135°<A/2<180°, so sinA/2 must be positive and the only correct answer is

sin A/2= 1/sqrt10

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The circumference of the inner circle is 270.04 miles. What is the area of the shaded region?
Shalnov [3]
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