ok is there more info about it
Answer:
<h2>The range: {-6, -10, -14, -18}</h2>
Step-by-step explanation:
Put the values of x from the domain to the equation of a function y = 4x - 2:
for x = -1
y = 4(-1) - 2 = -4 - 2 = -6
for x = -2
y = 4(-2) - 2 = -8 - 2 = -10
for x = -3
y = 4(-3) - 2 = -12 - 2 = -14
for x = -4
y = 4(-4) - 2 = -16 - 2 = -18
Answer:
Ok, the domain is the set of values that we can input in a function.
In this case, we have:
y = Ix - 6I + 3.
Notice that there is no restriction here, x can actually take any value, then the domain will be the set of all real numbers.
The correct domain is x, x ∈ R
Now, if we had (for example) something like:
y = Ix - 6I < 3
Now we have a restriction in the domain because we can not have y equal or larger than 3.
To find the domain, we can break the absolute value:
Ix - 6I < 3
is equivalent to:
-3 < x - 6 < 3
now let's add 6 in each side.
-3 + 6 < x - 6 + 6 < 3 + 6
3 < x < 9
That will be the domain in that case.
Answer:
A. ![\sqrt[3]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%7D)
= Cube root of 4.
Step-by-step explanation:
We have been given an expression 
. We are asked to find the equivalent expression for our given expression.
Using exponent property ![\sqrt[n]{a^m} =a^{\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Em%7D%20%3Da%5E%7B%5Cfrac%7Bm%7D%7Bn%7D)
, we will get,
![2^{\frac{2}{3}}=\sqrt[3]{2^2}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B2%5E2%7D)
![2^{\frac{2}{3}}=\sqrt[3]{4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B4%7D)
Upon looking at our given choices, we can see that option A is the correct choice.
F(x) = 112 - kx
f(-3) = 121
f(-3) = 112 - k(-3)
f(-3) = 112 + 3k
121 = 112 + 3k
121 - 112 = 3k
9 = 3k
9/3 = k
3 = k <===
