What kind of transformation is illustrated in this figure?

What is the period of the function F(x) = -4sec (1/2 x)

serg [7]

Answer:

A) 4π

Step-by-step explanation:

The period of a secant function, f(x)=a*sec(bx+c)+d, is defined as 2π/|b| where b is the distance of the period. Since we know b=1/2 given by the function, then the period is 2π/|1/2|=2π/(1/2)=2π(2/1)=4π.

8 0

2 years ago

10. The expression 3(2+x) is a product of the factors 3 and

Trava [24]

Answer:

Step-by-step explanation:

10. 2 ( 3 times 2 = 6, The three and two are both factors)

11. 3(2+x)= 6+3x If you do distributive property you have to multiply times 3 of everything in the parentheses

12. I don't see the image sorry.

4 0

3 years ago

Exercise 1.1. We roll a fair die twice. Describe a sample space ⌦ and a probability measure P to model this experiment. Let A be

3241004551 [841]

Answer:

$P=\frac{1}{36}$

$P(A)=\frac{5}{12}$

Step-by-step explanation:

The sample space of rolling a dice twice is:

S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

Sample size, n = 36.

Each sample has an equal chance of being selected.

So the probability of selecting any of the 36 sample is, $P=\frac{1}{36}$ .

Now an event A is defined as the second roll being larger than the first.

The sample space for A is:

A = {(2, 1), (3, 1), (3, 2), (4, 1), (4, 2), (4, 3), (5, 1), (5, 2), (5, 3), (5, 4), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5)}

The sample size is, n = 15.

The probability of the event A is:

$P(A)=\frac{15}{36}=\frac{5}{12}$

5 0

3 years ago

Write an equation for a circle with a diameter that has endpoints at (-10, 1) and (-8, 5). Round to the nearest tenth if necessa

kherson [118]

Answer:

The equation is (x+9)^2 + (y-3)^2 = 5

Step-by-step explanation:

The standard form for the equation of a circle is:

(x−h)^2+(y−k)^2=r2

The center of the circle is the midpoint of the diameter.

So the midpoint of the diameter at (-10, 1) and (-8, 5) can be determined as:

(-10 +(-8))/2 , (1+5)/2

= -10-8/2, 1+5/2

= -18/2 , 6/2

= -9 , 3

Thus(-9,3) is the center of the circle.

Now we will use the distance formula to find the radius of the circle.

r^2=(-10-(-9))^2 + (1-3)^2

r^2=(-10+9)^2 +(-2)^2

r^2=(-1)^2 + (-2)^2

r^2=1 + 4

r^2= 5

Take square root at both sides.

√r^2= √5

r=√5

Now put the values in the 1st equation.

(x−h)^2+(y−k)^2=r2

where h = -9, k =3 and r = √5

(x-(-9))^2 + (y-3)^2= (√5)^2

(x+9)^2 + (y-3)^2 = 5

Thus the equation is (x+9)^2 + (y-3)^2 = 5 ....

4 0

3 years ago

I need help on this, please. thanks

konstantin123 [22]

In the picture are the steps I used to solve it.

6 0

2 years ago

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