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3 years ago

PLS PLS PLS HELP!!!!!!!!!!

Mathematics

1 answer:

posledela3 years ago

7 0

The absolute value is c.8

absolute value is always positive the answer is never negative. mark me as brainliest:)

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A ball is thrown straight up with a initial velocity of 56 feet per second . The height , h , of the ball t seconds after it is

Tju [1.3M]

Formula: H(t) = 56t – 16t^2

H(t) = - 16t^2 + 56t

A. What is the height of the ball after 1 second? H (1) = 56(1) – 16(1) ^2 = 40 pt.

B. What is the maximum height? X = - (56)/2(- 16) = 1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.

C. After how many seconds will it return to the ground? – 16t^2 + 56t = 0 - 8t =0 t = 0

- 8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2 Ans: 3.5 seconds

3 0

3 years ago

Shade the model to show the decimal 0.542 using 100 grid and 10 grid

kherson [118]

0.542=0.500 + 0.040+0.002

= $\frac{5}{10} + \frac{4}{100} +\frac{2}{1000}$

=5 tenth + 4 hundredths + two thousandths

One tenth = $\frac{1}{10}$

One Hundredth= $\frac{1}{100}$

One thousandth= $\frac{1}{1000}$

8 0

3 years ago

Read 2 more answers

Rewrite 5ab showing the multiplication signs

monitta

Answer:

$5ab = 5 \times a \times b$

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Evaluate the expression 263 + 5 when b = 3. 263 +5 = 2(3): +5 =

ExtremeBDS [4]

Given:

The expression is:

$2b^3+5$

To find:

The value of the given expression when $b=3$ .

Solution:

We have,

$2b^3+5$

Substituting $b=3$ in the above expression, we get

$2b^3+5=2(3)^3+5$

$2b^3+5=2(27)+5$

$2b^3+5=54+5$

$2b^3+5=59$

Therefore, the value of given expression at $b=3$ is 59.

7 0

2 years ago

Read 2 more answers

1. What are foci? 2. What is the first step to take to write the equation of a hyperbola? 3. How do you represent parts of a hyp

Andrei [34K]

Answer: see below

Step-by-step explanation:

1) Foci is plural for Focus. Since a hyperbola has two focus points, they are referred to as foci. The foci is where the sum of the distances from any point on the curve to the foci is constant.

2) When determining the equation of a hyperbola you need the following:

a) does the hyperbola open up or to the right?

b) what is the center (h, k) of the hyperbola?

c) What is the slope of the asymptotes of the hyperbola?

3) The equation of a hyperbola is:

$\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1\qquad or\qquad \dfrac{(y-k)^2}{b^2}-\dfrac{(x-h)^2}{a^2}=1$

(h, k) is the center of the hyperbola
± b/a is the slope of the line of the asymptotes
The equation starts with the "x" if it opens to the right and "y" if it opens up

5 0

3 years ago