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Alekssandra [29.7K]
4 years ago
8

Suppose you are given the coordinates of the vertices of a polygon. What steps could you take to solve a problem involving the p

olygon's area?
Mathematics
1 answer:
Vikki [24]4 years ago
3 0
First find the length of all the sides.
Then divide that polygon (if it has more than 4 sides or an irregular quadrilateral) into triangles.
Find the area of triangles so formed by Heron's formula.
Than sum the area of all the triangles. The sum will be the area of the polygon.
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Anna and Bobie joined two different swimming classes at the same time.
jeyben [28]

Answer:

It would be 10 months for the price of $320.

Step-by-step explanation:

First we need to find how much Anna's swimming charge and Bobie's charge is.

PA=70+t The price of the month equals to the starting fee and monthly charge

120=70+2t The price of 2 months times the monthly charge

50=2t

25=t           is Anna's monthly charge

PB=250+t   is Bobies starting price and monthly charge

264=250+2t is the month charge for Bobie after 2 months

14=2t

7=t              is Bobie's monthly charge

70+25x=250+7x    We need to find x which is what month will satisfy both equations

25x=180+7x         Subtract 70 from both sides

18x=180                Subtract 7x from both sides

x=10                      divide 18 from both sides

Now we have the months that satisfy both equations we need to find the total price that matches with it. So we plug it back into both equations.

PA=70+25x                                               PB=250+7x

PA=70+25(10)                                            PB=250+7(10)

PA=70+250                                               PB=250+70

PA=320                                                      PB=320

6 0
3 years ago
Read 2 more answers
HELP PLS ill mark u brainliest
ryzh [129]

Answer:

11

Step-by-step explanation:

Since angle 11 is next to angle 12, and they should add up to 180 degrees, which makes them supplementary angles.

4 0
3 years ago
Read 2 more answers
ASAP PLEASE<br><br> What is the slope of the equation 2 y = 6 x - 8?
Effectus [21]

Answer:

3

Step-by-step explanation:

divide the equation by two

to make the equation equal to y

so y=(6x-8)/2

y=3x-4

y=mx+b

m=slope

b=y intercept

so 3=slope

Hope that helps :)

5 0
3 years ago
Okay dudes and dudets wanna help me out heres the problem
olga2289 [7]

\bf \begin{array}{|c|c|l} \cline{1-2} \stackrel{\textit{years after 2000}}{x}&\stackrel{\textit{millions of volunteers}}{y}\\ \cline{1-2} 4&6.1\\ 10&11.1 \\ \cline{1-2} \end{array} \qquad \qquad (\stackrel{x_1}{4}~,~\stackrel{y_1}{6.1})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{11.1})


\bf slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{11.1-6.1}{10-4}\implies \cfrac{5}{6} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-6.1=\cfrac{5}{6}(x-4)\implies y-6.1=\cfrac{5}{6}x-\cfrac{10}{3} \\\\\\ y=\cfrac{5}{6}x-\cfrac{10}{3}+6.1\implies y=\cfrac{5}{6}x-\cfrac{10}{3}+\cfrac{61}{10}\implies \blacktriangleright y=\cfrac{5}{6}x+\cfrac{83}{30} \blacktriangleleft


now, for 2009, that's 9 years after 2000 so x = 9, and 2014, well clearly x = 14, so


\bf \stackrel{x = 9}{y=\cfrac{5}{6}(9)+\cfrac{83}{30}}\implies y=\cfrac{15}{2}+\cfrac{83}{30}\implies y=\cfrac{154}{15}\implies y=10\frac{4}{15} \\\\\\ \stackrel{x = 14}{y=\cfrac{5}{6}(14)+\cfrac{83}{30}}\implies y=\cfrac{35}{3}+\cfrac{83}{30}\implies y=\cfrac{433}{30}\implies y=14\frac{13}{30}

5 0
3 years ago
How can you show the number 54 two different ways?explain using your words.
LekaFEV [45]

You could label fifty four as x and have it as x=54

6 0
3 years ago
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