What is the maximum number of relative extrema contained in the graph of this function f(x)=3x^3-x^2+4x-2

2 answers:

5 0

The maximum number of turning points in a cubic function is 2.

In this case,

$f(x)=3x^3-x^2+4x-2\implies f'(x)=9x^2-2x+4$

The discriminant is $(-2)^2-4(9)(4)=-140$ , which means the derivative has no real roots. This means there are no critical points and thus no turning points/relative extrema.

sergeinik [125]3 years ago

5 0

Answer:

the answer is 2 (apex)

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