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3 years ago

What is 86/0.4 Please Help

Mathematics

1 answer:

IrinaK [193]3 years ago

5 0

Answer:

2150

Step-by-step explanation:

86/.4=2150

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What is m CDJ? please help me I'm super confused.

Citrus2011 [14]

Answer:

34 degrees.

Step-by-step explanation:

Assuming AK is a straight line and being shown angle JDK is right and 90 degrees it can be stated that 4x + (3x-8) = 90 degrees.

Drop the parentheses and get 7x - 8 = 90.

Add 8 to both sides 7x = 98.

Divide both sides by 7, x = 14.

Plug that x value into (3x-8), [3(14)-8] = 34 degrees.

8 0

2 years ago

Read 2 more answers

Explain how to graph the in inequality 8>y

insens350 [35]

Answer:

How to Graph a Linear Inequality

First, graph the "equals" line, then shade in the correct area.

There are three steps:

1.) Rearrange the equation so "y" is on the left and everything else on the right.

2.) Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)

4.) Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).

Hope This Helps! Have A Nice Day!!

8 0

3 years ago

Find the distance between the points with the given coordinates (-8,-6),(4,10)

Serggg [28]

Hello from MrBillDoesMath!

Answer:

Discussion:

Let (x1,y1) = (-8, -6) and (x2,y2) = (4,10). Per the distance formula,

Distance = sqrt ( (x1-x2)^2 + (y1-y2)^2 ) so

Distance = sqrt ( (-8-4)^2 + (-6-10)^2 )

= sqrt( (12)^2 + (-16)^2 )

= sqrt( 144 + 256 )

= sqrt(400)

= 20

Thank you,

MrB

3 0

3 years ago

Read 2 more answers

The complement of an angle is 25. What is the measure of an angle

Inessa [10]

The complement of an acute angle A in degrees is 90 - A. So if the complement is 25 degrees, the angle would be 90 - 25 = 65 degrees.

8 0

3 years ago

Pls help asap whats the local min value of the function below?

shutvik [7]

Answer:

given function has 2 minimums - $\frac{9}{4}$ and $\frac{9}{4}$

Step-by-step explanation:

Step 1. g'(x) = 4x³ - 10x

Step 2. Find find the critical points:

4x³ - 10x = 2x(2x² - 5) = 0

$x_{1}$ = - $\sqrt{\frac{5}{2} }$ , $x_{2}$ = 0 , $x_{3}$ = $\sqrt{\frac{5}{2} }$

Step 3. g'(x) > 0 : - $\sqrt{\frac{5}{2} }$ < x < 0 or x > $\sqrt{\frac{5}{2} }$

g'(x) < 0 : x < - $\sqrt{\frac{5}{2} }$ or 0 < x < $\sqrt{\frac{5}{2} }$

Step 4.

If x ∈ ( - ∞ , - $\sqrt{\frac{5}{2} }$ ) , g(x) is decreasing ;

If x = - $\sqrt{\frac{5}{2} }$ , g(x) has minimum value ;

If x ∈ ( - $\sqrt{\frac{5}{2} }$ , 0 ) , g(x) is increasing ;

If x = 0 , g(x) has maximum value ;

If x ∈ ( 0 , $\sqrt{\frac{5}{2} }$ ) , g(x) is decreasing ;

If x = $\sqrt{\frac{5}{2} }$ , g(x) has minimum value ;

If x ∈ ( $\sqrt{\frac{5}{2} }$ , ∞ ) , g(x) is increasing .

⇒ at ( - $\sqrt{\frac{5}{2} }$ , - $\frac{9}{4}$ ) and at ( $\sqrt{\frac{5}{2} }$ , $\frac{9}{4}$ ) , g(x) reaches its minimum

8 0

3 years ago