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antiseptic1488 [7]
2 years ago
11

Find two numbers whose product is 110, and whose sum is 21.

Mathematics
1 answer:
shutvik [7]2 years ago
6 0

Answer:

10 and 11

10 \times 11 = 110

10 + 11 = 21

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I think is 12 .......
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Oxana [17]

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1

Step-by-step explanation:

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Which shows one way to determine the factors of x^3 - 9x^2 + 5x - 45 by grouping ?
adoni [48]
You can group first two conjunctions and second two:
x^3 - 9x^2 + 5x - 45=(x^3-9x^2)+(5x-45).
In first brackets you have common x^2 and in second brackets common is 5:
(x^3-9x^2)+(5x-45)=x^2(x-9)+5(x-9)=(x-9)(x^2+5).
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Answer:

9 1/3, 12 1/2, 14 3/4

Step-by-step explanation:

I assume the formula you’re working with is A=b*h since nothing says otherwise...

((Patio 1))

So you have your area (147) and your base (15 3/4), now you need to plug them in, which should look like this:

147= 15 3/4*h

You need to isolate your h in order to get the missing number, so you should divide both sides by 15 3/4 OR 63/4 ((15*3—>60+3=63))

Dividing by a fraction is the equivalent of multiplying by its reciprocal... so

147 * 4/63 = 588/63 which can be simplified to 84/9 once both the numerator and denominator are divided by 7

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3 years ago
4n^(2)+4n=3<br> Please help with the work
Kaylis [27]

Answer:

n= 1/2 ( \frac{1}{2} )  or  (0.5)

AND

n= -3/2 ( -\frac{3}{2} ) or (-1.5)

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4n^2+4n=3

step1: move 3 to the other side and make the equation equal to zero.

4n^2+4n-3=0

step2: factorise the equation.

(2n-1)(2n+3)=0

step3: make each bracket equal to zero.

2n-1=0

2n+3=0

step4: solve for n values.

<u>1.</u> 2n-1=0

(add 1 for both sides)

2n=1

(divide by 2 for both sides)

n= 1/2 ( \frac{1}{2} )  or  (0.5)

<u>2.</u> 2n+3=0

( subtract 3 for both sides)

2n=-3

(divide by 2 for both sides)

n= -3/2 ( -\frac{3}{2} ) or (-1.5)

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