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Harlamova29_29 [7]
3 years ago
10

What is the numerator in the final expression of x/2+y/6-z/4

Mathematics
1 answer:
olasank [31]3 years ago
7 0

interpretation: x/2+y/6-z/4

Input:

x/2 + y/6 - z/4

Alternate form:

1/12 (6 x + 2 y - 3 z)

Real root:

z = 2 x + (2 y)/3

Root:

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4. A school is conducting a fundraiser by selling sweatshirts. The school marks op the price
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Is {(2,4)(3, 4). (4,4), (5, 6)} a relation?*
kirill115 [55]

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2 years ago
WILL MARK BRAINLIEST!
Artist 52 [7]

Answer:

Following are the responses to the given points:

Step-by-step explanation:

Dilation implies the triangle \Delta XYZ stretched through the factor "2".  

m\angle Y = m\angle C = 90^{\circ} \leftarrow given \\\\  

right triangles:

\Delta  XYZ and \Delta  ACB \\\\\angle X \cong \angle A \leftarrow given\\\\

complementary angles:  

\angle X \ and\  \angle Z

m\angle Z = 90^{\circ} - m\angle X \\\\

complementary angles:

\angle A \ and\  \angle B

m\angle B = 90^{\circ} - m\angle A \\\\\therefore \\\\ \angle Z \cong \angle B \\\\\Delta  XYZ \sim  \Delta ACB \\\\

Same triangles: proportional side are corresponding, congruence angles are respective.

\sin \angle X = \frac{5}{5.59} \leftarrow given \\\\\sin\angle X = \frac{YZ}{XY} \\\\YZ = 5 (units) \rightarrow leg in \Delta XYZ \\\\XZ = 5.59 (units) \rightarrow hypotenuse \ in\  \Delta XYZ\\\\

Calculating the length of leg XY:

XY = \sqrt{((5.59)^2 - 52)} \cong 2.4996 (units)\\\\\frac{CB}{YZ} = 2 \leftarrow given \\\\CD = 2YZ = 2 \times 5 = 10 \ (units)\\\\\frac{AC}{XY} = 2 \leftarrow  \ given\\\\AC = 2XY \cong 2 \times  2.4996 \cong 4.999\  (units)\\\\

3 0
2 years ago
A vase has the shape of a rectangular prism. The inside of the vase is also a rectangular prism. What is the volume of the solid
saw5 [17]

Answer:

V_{s} = \frac{\pi}{4}\cdot D_{out}^{2} \cdot h -\frac{\pi}{4}\cdot (D_{out}-2\cdot t)^{2}\cdot (h-t)

Step-by-step explanation:

The geometric description of the vase is described in the image attached below. The volume of the solid part of the vase is:

V_{s} = V_{out} - V_{in}

V_{s} = \frac{\pi}{4}\cdot D_{out}^{2} \cdot h -\frac{\pi}{4}\cdot (D_{out}-2\cdot t)^{2}\cdot (h-t)

Where:

D_{out} - Outer diameter, in centimeters.

t - Vase thickness, in centimeters.

3 0
3 years ago
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