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kogti [31]
2 years ago
5

What value of x makes this equation TRUE? 4x + 2 = −14

Mathematics
1 answer:
Veronika [31]2 years ago
7 0

4x + 2 = -14

4x = -16

x = -4

4(-4) + 2 = -14

-16 + 2 = -14

-14 = -14

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

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qwelly [4]
Answer:
1) correct
2) correct
3) Not Congruent
4) Not Congruent
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6) Not Congruent
7) incorrect
8) SAS

Explanation:
7 is incorrect because the angle isn’t included in the sides

Hope this helps!
7 0
3 years ago
A random sample of 12 recent college graduates reported an average starting salary of $54,000 with a standard deviation of $6,00
Marianna [84]

Answer: a.) $50188 to $57812

Step-by-step explanation: <u>Confidence</u> <u>Interval</u> (CI) is an interval of values in which we are confident the true mean is in.

The interval is calculated as

x ± z\frac{s}{\sqrt{n} }

a. For a 95% CI, z-value is 1.96.

Solving:

54,000 ± 1.96.\frac{6000}{\sqrt{12} }

54,000 ± 1.96\frac{6000}{3.464}

54,000 ± 1.96*1732.102

54,000 ± 3395

This means the interval is

50605 < μ < 57395

<u>With a 95% confidence interval, the mean starting salary of college graduates is between 50605 and 57395 or </u><u>from 50188 to 57812$.</u>

<u />

b. The mean starting salary for college students in 2017 is $50,516, which is in the confidence interval. Therefore, since we 95% sure the real mean is between 50188 and 57812, there was no significant change since 2017.

4 0
2 years ago
How would you describe the correlation in the data? Explain your reasoning. (2 points).
ANTONII [103]

Answer:

Hi

Step-by-step What is a linear function in the form y= mx + b for the line passing through (4.5, -4.25) with y-intercept 2.5 yup help pleade

5 0
2 years ago
Can someone help me solve this?
Sladkaya [172]

Step-by-step explanation:

yan po ang sagot ko dahil yan po ang pagkakaintindi ko

6 0
2 years ago
A random sample of 23 items is drawn from a population whose standard deviation is unknown. The sample mean isx⎯ ⎯ x¯ = 840 and
gayaneshka [121]

Answer:

(832.156, \ 847.844)

Step-by-step explanation:

Given data :

Sample standard deviation, s = 15

Sample mean, \overline x = 840

n = 23

a). 98% confidence interval

$\overline x \pm t_{(n-1, \alpha /2)}. \frac{s}{\sqrt{n}}$

$E= t_{( n-1, \alpha/2 )} \frac{s}{\sqrt n}}

$t_{(n-1 , \alpha/2)} \frac{s}{\sqrt n}$

$t_{(n-1, a\pha/2)}=t_{(22,0.01)} = 2.508$

∴ $E = 2.508 \times \frac{15}{\sqrt{23}}$

  $E = 7.844$

So, 98% CI is

$(\overline x - E, \overline x + E)$

(840-7.844 ,  \ 840+7.844)

(832.156, \ 847.844)

4 0
2 years ago
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