Ask question

Ask question

All categories

tino4ka555 [31]

3 years ago

5

Solve equation 1/2(4d - 2) = d + 5

2 answers:

kogti [31]3 years ago

7 0

The answer is d=6 i can show my work in the comments if you need it

algol [13]3 years ago

7 0

Hello there,

There is only one solution for your equation. The answer is d = 6. If you need to see more steps on how to find the answer you can use this link: https://www.tiger-algebra.com/drill/1/2(4d-2)=d_5/.

Hope this answer has helped you. If it has, please help me out by giving this answer brainliest.

Have a wonderful day

You might be interested in

You are graphing Square ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the square: A(4,

Kitty [74]

Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

The diagonals are BD and AC

Midpoint of BD = Midpoint of AC

$\left(\dfrac{8+x}{2},\dfrac{-7+y}{2}\right) =\left(\dfrac{4+8}{2},\dfrac{-7+(-3)}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(\dfrac{12}{2},\dfrac{-10}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(6,-5\right)\\$Therefore$:\\\dfrac{8+x}{2}=6\\8+x=12\\x=12-8\\x=4\\$Similarly$\\\dfrac{y-7}{2}=-5\\y-7=-5*2\\y-7=-10\\y=-10+7=-3$

The coordinates of the fourth vertex is D(4,-3)

3 0

4 years ago

Help??? What is the volume of this right cone? 27π cm³ 200π cm³ 213π cm³ 300π cm³ NOTE: Image is not drawn to scale.

yuradex [85]

Answer:

Step-by-step explanation:

V=1/3 π 10²×9=300 π cm³

6 0

3 years ago

Read 2 more answers

Write the value of the digit 0.287

Cerrena [4.2K]

<span>___________________▄▄▄▀▀▀▀▀▀▀▄ _______________▄▀▀____▀▀▀▀▄____█ ___________▄▀▀__▀▀▀▀▀▀▄___▀▄___█ __________█▄▄▄▄▄▄_______▀▄__▀▄__█ _________█_________▀▄______█____█_█ ______▄█_____________▀▄_____▐___▐_▌ ______██_______________▀▄___▐_▄▀▀▀▄ ______█________██_______▌__▐▄▀______█ ______█_________█_______▌__▐▐________▐ _____▐__________▌_____▄▀▀▀__▌_______▐_____________▄▄▄▄▄▄ ______▌__________▀▀▀▀________▀▀▄▄▄▀______▄▄████▓▓▓▓▓▓▓███▄ ______▌____________________________▄▀__▄▄█▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▄ ______▐__________________________▄▀_▄█▓▓▓▓▓▓▓▓▓▓_____▓▓____▓▓█▄ _______▌______________________▄▀_▄█▓▓▓▓▓▓▓▓▓▓▓____▓▓_▓▓_▓▓__▓▓█ _____▄▀▄_________________▄▀▀▌██▓▓▓▓▓▓▓▓▓▓▓▓▓__▓▓▓___▓▓_▓▓__▓▓█ ____▌____▀▀▀▄▄▄▄▄▄▄▄▀▀___▌█▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓__▓________▓▓___▓▓▓█ _____▀▄_________________▄▀▀▓▓▓▓▓▓▓▓█████████████▄▄_____▓▓__▓▓▓█ _______█▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓█▓▓▓▓▓██▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓██▄▄___▓▓▓▓▓█ _______█▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓█▓▓███▓▓▓▓████▓▓▓▓▓▓▓▓▓▓▓▓▓██▓▓▓▓▓▓█ ________█▓▓▓▓▓▓▓▓▓▓▓▓▓▓█▓█▓▓██░░███████░██▓▓▓▓▓▓▓▓▓▓██▓▓▓▓▓█ ________█▓▓▓▓▓▓▓▓▓▓▓▓▓▓██▓░░░░░█░░░░░██░░░░██▓▓▓▓▓▓▓▓▓██▓▓▓▓▌ ________█▓▓▓▓▓▓▓▓▓▓▓▓▓▓███░░░░░░░░____░██░░░░░░░██▓▓▓▓▓▓▓██▓▓▌ ________▐▓▓▓▓▓▓▓▓▓▓▓▓▓▓██░░░░░░░________░░░░░░░░░██████▓▓▓▓▓█▓▌ ________▐▓▓▓▓▓▓▓▓▓▓▓▓▓▓██░░░░░░___▓▓▓▓▓░░░░░░░███░░███▓▓▓▓▓█▓▌ _________█▓▓▓▓▓▓▓▓▓▓▓▓▓██░░░░░___▓▓█▄▄▓░░░░░░░░___░░░░█▓▓▓▓▓█▓▌ _________█▓▓▓▓▓▓▓▓▓▓▓▓▓█░░█░░░___▓▓██░░░░░░░░▓▓▓▓__░░░░█▓▓▓▓██ _________█▓▓▓▓▓▓▓▓▓▓▓▓▓█░███░░____▓░░░░░░░░░░░█▄█▓__░░░░█▓▓█▓█ _________▐▓▓▓▓▓▓▓▓▓▓▓▓▓█░█████░░░░░░░░░░░░░░░░░█▓__░░░░███▓█ __________█▓▓▓▓▓▓▓▓▓▓▓▓█░░███████░░░░░░░░░░░░░░░▓_░░░░░██▓█ __________█▓▓▓▓▓▓▓▓▓▓▓▓█░░░███████░░░░░░░░░░░░░░_░░░░░██▓█ __________█▓▓▓▓▓▓▓▓▓▓▓▓█░░░███████░░░░░░░░░░░░░░░░░░░██▓█ ___________█▓▓▓▓▓▓▓▓▓▓▓▓█░░░░███████░░░░░░░░░░░█████░██░░░ ___________█▓▓▓▓▓▓▓▓▓▓▓▓█░░░░░░__███████░░░░░███████░░█░░░░ ___________█▓▓▓▓▓▓▓▓▓▓▓▓▓█░░░░░░█▄▄▄▀▀▀▀████████████░░█░░░░ ___________▐▓▓▓▓▓▓▓▓▓▓▓▓█░░░░░░██████▄__▀▀░░░███░░░░░█░░░ ___________▐▓▓▓▓▓▓▓▓▓▓▓█▒█░░░░░░▓▓▓▓▓███▄░░░░░░░░░░░░░░░______▄▄▄ ___________█▓▓▓▓▓▓▓▓▓█▒▒▒▒█░░░░░░▓▓▓▓▓█░░░░░░░░░░░░░░░▄▄▄_▄▀▀____▀▄ __________█▓▓▓▓▓▓▓▓▓█▒▒▒▒█▓▓░░░░░░░░░░░░░░░░░░░░░____▄▀____▀▄_________▀▄ _________█▓▓▓▓▓▓▓▓▓█▒▒▒▒█▓▓▓▓░░░░░░░░░░░░░░░░░______▐▄________█▄▄▀▀▀▄__█ ________█▓▓▓▓▓▓▓▓█▒▒▒▒▒▒█▓▓▓▓▓▓▓░░░░░░░░░____________█_█______▐_________▀▄▌ _______█▓▓▓▓▓▓▓▓█▒▒▒▒▒▒███▓▓▓▓▓▓▓▓▓▓▓█▒▒▄___________█__▀▄____█____▄▄▄____▐ ______█▓▓▓▓▓▓▓█_______▒▒█▒▒██▓▓▓▓▓▓▓▓▓▓█▒▒▒▄_________█____▀▀█▀▄▀▀▀___▀▀▄▄▐ _____█▓▓▓▓▓██▒_________▒█▒▒▒▒▒███▓▓▓▓▓▓█▒▒▒██________▐_______▀█_____________█ ____█▓▓████▒█▒_________▒█▒▒▒▒▒▒▒▒███████▒▒▒▒██_______█_______▐______▄▄▄_____█ __█▒██▒▒▒▒▒▒█▒▒____▒▒▒█▒▒▒▒▒▒▒▒▒▒▒▒▒▒█▒____▒█▓█__▄█__█______▀▄▄▀▀____▀▀▄▄█ __█▒▒▒▒▒▒▒▒▒▒█▒▒▒████▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█_______█▓▓█▓▓▌_▐________▐____________▐ __█▒▒▒▒▒▒▒▒▒▒▒███▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█▒_______█▓▓▓█▓▌__▌_______▐_____▄▄____▐ _█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█▒▒_____█▓▓▓█▓▓▌__▌_______▀▄▄▀______▐ _█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒███████▓▓█▓▓▓▌__▀▄_______________▄▀ _█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒███▒▒▒▒▒▒▒██▓▓▓▓▓▌___▀▄_________▄▀▀ █▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒██▒▒▒▒▒▒▒▒▒▒▒▒▒█▓▓▓▓▓▀▄__▀▄▄█▀▀▀ █▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒██▓▓▓▓██▄▄▄▀ █▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒████ █▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█ _█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█▒▒▒█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█▄▄▄▄▄ _█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█▒▒▒▒█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒███▒▒▒▒▒▒██▄▄ __█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█▒▒▒▒█▒▒▒▒▒▒▒▒▒▒▒▒███▒▒▒▒▒▒▒▒▒▒▒▒▒█▄ __█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█▒▒▒▒█▒▒▒▒▒▒▒▒▒▒▒█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█ __█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█▒▒▒▒█▒▒▒▒▒▒▒▒▒██▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█ ___█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█▒▒▒▒█▒▒▒▒▒▒▒▒█▒▒▒▒▒▒▒▒▒▒▒▒▒░░░░▒▒▒▒▒▒▌ ____█▒▒▒▒▒▒▒▒▒▒▒▒▒██▒▒▒▒▒▒▒█▒▒▒▒█▒▒▒▒▒▒█▒▒▒▒▒▒▒▒▒░░░░░░░░░░░░░▒▒▌ ____█▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒█████████████▒▒▒▒▒█▒▒▒▒▒▒▒▒░░░░▒▒▒▒▒▒▒▒▒▒▒░▒▌ _</span>

8 0

3 years ago

Consider the infinite region bounded by the curves y=1/x, x=1, and the x-axis. Show that the solid obtained by rotating this reg

solmaris [256]

Can you j the question more sorry i just cant find the comment so i used this.

5 0

3 years ago

3m by 2m how many square meters

REY [17]

Answer:

6 m^2

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers