9(3+5) is equivalent because factoring a 9 out of both 27 and 45 leaves us with 9(3+5).
Set each equation equal to zero.
y + 5 = 0
Subtract 5 from both sides.
y = 0 - 5
y = - 5
y - 9 = 0
Add 9 to both sides
y = 0 + 9
y = 9
y = - 5, 9
36/30=1.2
30/1.2=25
3x+4=25
3x=21
X=7
Therefore a is your answer
Hope this helps
I assume you mean:
3x^2 -5xy + 5y^2.
Simply substitute the given values into the equation:
3(-6)^2 - 5(-6)(2) + 5(2)^2
=188

Multiply both sides of the equation by 20, the lowest common denominator of 5,4,2.

Add 4 and 3 to get 7.

Use the distributive property to multiply −4 times x 4/7.

Multiply −4 by 4/7.
![\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10(2\times2+1) \ \ \to \ \ [Multiply \ 2\times2] } \end{gathered}$}](https://tex.z-dn.net/?f=%5Clarge%5Cdisplaystyle%5Ctext%7B%24%5Cbegin%7Bgathered%7D%5Csf%20%5Cbf%7B-4x-7%3D10%282%5Ctimes2%2B1%29%20%5C%20%5C%20%5Cto%20%5C%20%5C%20%5BMultiply%20%5C%202%5Ctimes2%5D%20%7D%20%20%5Cend%7Bgathered%7D%24%7D)
![\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10(4+1) \ \ \to \ \ [Add] } \end{gathered}$}](https://tex.z-dn.net/?f=%5Clarge%5Cdisplaystyle%5Ctext%7B%24%5Cbegin%7Bgathered%7D%5Csf%20%5Cbf%7B-4x-7%3D10%284%2B1%29%20%5C%20%5C%20%5Cto%20%5C%20%5C%20%5BAdd%5D%20%7D%20%20%5Cend%7Bgathered%7D%24%7D)
![\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10\times5 \ \ \to \ \ [Multiply] } \end{gathered}$}](https://tex.z-dn.net/?f=%5Clarge%5Cdisplaystyle%5Ctext%7B%24%5Cbegin%7Bgathered%7D%5Csf%20%5Cbf%7B-4x-7%3D10%5Ctimes5%20%5C%20%5C%20%5Cto%20%5C%20%5C%20%5BMultiply%5D%20%7D%20%20%5Cend%7Bgathered%7D%24%7D)

Add 7 to both sides.
![\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x=-50+7 \ \ \to \ \ [Add] } \end{gathered}$}](https://tex.z-dn.net/?f=%5Clarge%5Cdisplaystyle%5Ctext%7B%24%5Cbegin%7Bgathered%7D%5Csf%20%5Cbf%7B-4x%3D-50%2B7%20%5C%20%5C%20%5Cto%20%5C%20%5C%20%5BAdd%5D%20%7D%20%5Cend%7Bgathered%7D%24%7D)

Divide both sides by −4.

The fraction
can be simplified to
by removing the negative sign from the numerator and denominator.

simplify

<h2>{ Pisces04 }</h2>